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rusak2 [61]
3 years ago
14

Nitrous oxide is used as an anesthetic. The pressure on 2.50 L of N2O changes from 105 kPa to 40.5 kPa. If the temperature does

not change, what will the new volume be?

Chemistry
1 answer:
Alchen [17]3 years ago
4 0
。。。。。。。。。。。。。。。。。。。。。。。。

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This is science
irakobra [83]

Answer:

a= seismic waves I think

b= outer

c= crust I think

6 0
3 years ago
Milkweed contains a poison known as cardenolides. Monarch butterflies eat the milkweed plant and hold on to this toxic compound.
igor_vitrenko [27]

Answer:

the answer is D) 23 carbon atoms, 34 hydrogen atoms, and 2 oxygen atoms

Explanation:

i took the test and got a 100%

4 0
2 years ago
A 360. g iron rod is placed into 750.0 g of water at 22.5°C. The water temperature rises to 46.7°C. What was the initial tempera
Grace [21]

Answer: The initial temperature of the iron was 515^0C

Explanation:

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of iron = 360 g

m_2 = mass of water = 750 g

T_{final} = final temperature = 46.7^0C

T_1 = temperature of iron = ?

T_2 = temperature of water = 22.5^oC

c_1 = specific heat of iron = 0.450J/g^0C

c_2 = specific heat of water= 4.184J/g^0C

Now put all the given values in equation (1), we get

-360\times 0.450\times (46.7-x)=[750\times 4.184\times (46.7-22.5)]

T_i=515^0C

Therefore, the initial temperature of the iron was 515^0C

4 0
3 years ago
546.8910 - 32.9 = ? Remember to use the appropriate significant figures.
dybincka [34]

513.991

Explanation:

546.8910

- 32.9

-----------

513.991

-----------

did this help ??

4 0
3 years ago
How many grams of NaCL are required to prepare 50ml of a 2.0 molar solution​
Ksivusya [100]

Answer:

5.85 gm.

Explanation:

We know that,

Normality =<u> Molarity × Molecular </u><u>weight</u>

Equivalent weight

Since molecular weight of NaCl= equivalent weight = 23+35.5 =58.5

Normality of NaCl= molarity=2

Now,

Normality= <u>weight</u><u> </u><u>in</u><u> </u><u>gram</u><u> </u><u>×</u><u>1000</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>

Volume ×equivalent weight

Weight in gram is given by,

<u>=</u><u>Normality × Volume × equivalent </u><u>weight</u>

1000

= <u>2× 50 × 58.</u><u>5</u>

1000

=5.85 gm.

4 0
3 years ago
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