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3 years ago

9

Which equation describes a reduction?

2 answers:

strojnjashka [21]3 years ago

8 0

Answer:

2Cl+2e -->2Cl^-

Explanation:

reduction is the gain of electrons and this is the only option which fits the definition.

Daniel [21]3 years ago

8 0

Answer:

2 Cl + 2 e⁻ → 2 Cl⁻

Explanation:

<em>Which equation describes a reduction?</em>

<em>Mg(s) → Mg²⁺(aq) + 2 e⁻.</em> NO. This is an oxidation because Mg loses electrons and its oxidation number increases from 0 to 2.

<em>2 Cl + 2 e⁻ → 2 Cl⁻.</em> YES. This is a reduction because Cl gains electrons and its oxidation number decreases from 0 to 1-.

<em>Na(s) → Na⁺(aq) + e⁻.</em> NO. This is an oxidation because Na loses electrons and its oxidation number increases from 0 to 1.

<em>Al(s) → Al³⁺(aq) + 3 e⁻.</em> NO. This is an oxidation because Al loses electrons and its oxidation number increases from 0 to 3.

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Based on electronegativity, select the molecule with the most ionic character. Group of answer choices SBr2 OBr2 SeCl2 TeI2 SCl2

Basile [38]

Answer:

OBr₂

Explanation:

<em>The ionic character depends on the difference of electronegativity between the elements. The higher ΔEN, the greater the ionic character.</em>

SBr₂

ΔEN = |EN(S)-EN(Br)| = |2.5-2.8| = 0.3

OBr₂

ΔEN = |EN(O)-EN(Br)| = |3.5-2.8| = 0.7

SeCl₂

ΔEN = |EN(Se)-EN(Cl)| = |2.4-3.0| = 0.6

TeI₂

ΔEN = |EN(Te)-EN(I)| = |2.1-2.5| = 0.4

SCl₂

ΔEN = |EN(S)-EN(Cl)| = |2.5-3.0| = 0.5

OBr₂ is the molecule with the most ionic character.

4 0

3 years ago

Answer A B C and D please for my chemistry hw

r-ruslan [8.4K]

<u>Answer:</u> The equations are provided below.

<u>Explanation:</u>

Skeleton equations are defined as the equations which simply indicate the molecules that are involved in a chemical reaction. These equations are unbalanced equations.

Balanced equations are defined as the chemical equation in which number of individual atoms on the reactant side must be equal to the number of individual atoms on the product side.

For A:

Water decomposes in the direct current to form hydrogen and oxygen.

Skeleton Equation: $H_2O(l)\rightarrow H_2(g)+O_2(g)$

Balanced Equation: $2H_2O(l)\rightarrow 2H_2(g)+O_2(g)$

For B:

Mercury (II) oxide decomposes in heat to form mercury, oxygen.

Skeleton Equation: $HgO(s)\rightarrow Hg+O_2$

Balanced Equation: $2HgO(s)\rightarrow 2Hg+O_2$

For C:

Calcium carbonate when heated forms calcium oxide and carbon dioxide.

Skeleton Equation: $CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

Balanced Equation: $CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

For D:

Group 2 hydroxides, when heated forms oxide and water vapor.

Skeleton Equation: $Ca(OH)_2\rightarrow CaO+H_2O$

Balanced Equation: $Ca(OH)_2\rightarrow CaO+H_2O$

3 0

3 years ago

Please help me which one

mel-nik [20]

Non of the above because protons and neutrons don’t mix with each one there

3 0

2 years ago

What does the 32.06 represent?

lana [24]

The 32.06 represent The atomic mass, the average number of protons & neutrons

<h3>Further explanation </h3>

The Atomic Number (Z) indicates the number of protons in an atom of an element. If the atom is neutral then the number of protons will be equal to the number of electrons. So the atomic number can also indicate the number of electrons.

So atomic number = number of protons = number of electrons

Mass Number (A) is the sum of protons and neutrons

Mass Number (A) = Number of protons + Number of Neutrons

So that the relationship between atomic numbers and mass numbers can be formulated as follows:

Atomic Number (Z) = Mass Number (A) - Number of Neutrons

In the following element notation,

$\large {{{Z} \atop {A}} \right X}$

X = symbol of elemental atom

A = mass number

= number of protons + number of neutrons

Z = atomic number

= number of protons = number of electrons, on neutral elements

4 0

3 years ago

Which diagram shows how the particles of the solid substance will look after it has absorbed enough heat to melt partially ??

cricket20 [7]

It would be A, the molecules should be closely packed together but arranged randomly. :)

4 0

3 years ago