Answer:
The total momentum of the system before the collision is 5.334 kg-m/s towards left.
Explanation:
Given that,
Mass of the block A, 
Speed of block A, 
Mass of the block B, 
Mass of block B, 
Let p is the total momentum of the system before the collision. It is given by :

So, the total momentum of the system before the collision is 5.334 kg-m/s towards left. Hence, this is the required solution.
Answer:
dV/dt = 9 cubic inches per second
Explanation:
Let the height of the cylinder is h
Diameter of cylinder = height of the cylinder = h
Radius of cylinder, r = h/2
dh/dt = 3 inches /s
Volume of cylinder is given by

put r = h/2 so,

Differentiate both sides with respect to t.

Substitute the values, h = 2 inches, dh/dt = 3 inches / s

dV/dt = 9 cubic inches per second
Thus, the volume of cylinder increases by the rate of 9 cubic inches per second.
Kinetic energy = (1/2) (mass) (speed)²
Since the 'speed' in the KE formula is squared, if the car's speed
increases by 5 times, its kinetic energy increases by (5²) = 25 times.
The loss of kinetic energy in a skid is just the wo0rk done by friction
between the tires and pavement. So the skid distance is proportional
to the initial kinetic energy, and the car must skid 25 times as far when
it enters the skid at the higher speed.
25 x 30m = 750 meters
PVI, so the power used would be 240*5= 1200 Watts.