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Maru [420]
2 years ago
7

the motion of a particle along a straight line is represented by the position versus time graph above. at which of the labeled p

oints on the graph is the magnitude of the acceleration of the particle greatest?
Physics
1 answer:
atroni [7]2 years ago
3 0

Point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.

On the graph, A is the point where magnitude of the acceleration of the particle is greatest as compared to other positions on the graph because the height of point A is the largest as compared to other points of the graph.

The graph shows at which point acceleration of an object is higher and lower so we can conclude that point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.

Learn more about acceleration here: brainly.com/question/933224

Learn more: brainly.com/question/25887663

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The Mass of a Body
9966 [12]

Answer:

Acceleration does not affect mass. Acceleration only affects weight.

Explanation:

Your mass is the same on Earth compared to on the moon, but your weight is going to be different because the acceleration due to gravity is going to be different.

7 0
3 years ago
A train travels 90 kilometers in 1 hours, and then 60 kilometers in 3 hours. What is its average speed
Serhud [2]
Average speed = (total distance) / (total time to cover the distance)

                       = (90km + 60km) / (1hr + 3hr)

                       =       (150 km)   /   (4 hr)

                       =          37.5 km/hr      . 
7 0
3 years ago
Which obkect shown on the grph below has the greatest acceleration
aleksklad [387]
Obkect-C has the greatest acceleration. (And it's negative.)
3 0
4 years ago
A hollow cylinder of mass 2.00 kgkg, inner radius 0.100 mm, and outer radius 0.200 mm is free to rotate without friction around
kipiarov [429]

Answer: 2.86 m

Explanation:

To solve this question, we will use the law of conservation of kinetic and potential energy, which is given by the equation,

ΔPE(i) + ΔKE(i) = ΔPE(f) + ΔKE(f)

In this question, it is safe to say there is no kinetic energy in the initial state, and neither is there potential energy in the end, so we have

mgh + 0 = 0 + KE(f)

To calculate the final kinetic energy, we must consider the energy contributed by the Inertia, so that we then have

mgh = 1/2mv² + 1/2Iw²

To get the inertia of the bodies, we use the formula

I = [m(R1² + R2²) / 2]

I = [2(0.2² + 0.1²) / 2]

I = 0.04 + 0.01

I = 0.05 kgm²

Also, the angular velocity is given by

w = v / R2

w = 4 / (1/5)

w = 20 rad/s

If we then substitute these values in the equation we have,

0.5 * 9.8 * h = (1/2 * 0.5 * 4²) + (1/2 * 0.05 * 20²)

4.9h = 4 + 10

4.9h = 14

h = 14 / 4.9

h = 2.86 m

8 0
3 years ago
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I'm pretty sure its a Neap Tide.
5 0
4 years ago
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