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il63 [147K]
3 years ago
11

Is the correct pls help me!! I will mark you!!!

Mathematics
2 answers:
wel3 years ago
6 0

Answer:

this it the answer i think

Step-by-step explanation:

as you can see in the picture below, i graphed the points and this is the function. i hope this helped!

ivolga24 [154]3 years ago
5 0

Answer:

-10 3

-9 4

-8 5

-3 10

Step-by-step explanation:

.........

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Step-by-step explanation:

Not all operations, only multiplication and division is done on both, numerator and denominator. So that the fraction value doesn't change (like eqivalent fractions)

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What is the standard form of 5.58 x 10^-2
alukav5142 [94]

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0.0558

Step-by-step explanation:

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3 years ago
A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si
Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

Area = 128

Let the dimension of the paper be x and y;

Such that:

Length = x

Width = y

So:

Area = x * y

Substitute 128 for Area

128 = x * y

Make x the subject

x = \frac{128}{y}

When 1 inch margin is at top and bottom

The length becomes:

Length = x + 1 + 1

Length = x + 2

When 2 inch margin is at both sides

The width becomes:

Width = y + 2 + 2

Width = y + 4

The New Area (A) is then calculated as:

A = (x + 2) * (y + 4)

Substitute \frac{128}{y} for x

A = (\frac{128}{y} + 2) * (y + 4)

Open Brackets

A = 128 + \frac{512}{y} + 2y + 8

Collect Like Terms

A = \frac{512}{y} + 2y + 8+128

A = \frac{512}{y} + 2y + 136

A= 512y^{-1} + 2y + 136

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

A' = -512y^{-2} + 2

Set

A' = 0

This gives:

0 = -512y^{-2} + 2

Collect Like Terms

512y^{-2} = 2

Multiply through by y^2

y^2 * 512y^{-2} = 2 * y^2

512 = 2y^2

Divide through by 2

256=y^2

Take square roots of both sides

\sqrt{256=y^2

16=y

y = 16

Recall that:

x = \frac{128}{y}

x = \frac{128}{16}

x = 8

Recall that the new dimensions are:

Length = x + 2

Width = y + 4

So:

Length = 8 + 2

Length = 10

Width = 16 + 4

Width = 20

To double-check;

Differentiate A'

A' = -512y^{-2} + 2

A" = -2 * -512y^{-3}

A" = 1024y^{-3}

A" = \frac{1024}{y^3}

The above value is:

A" = \frac{1024}{y^3} > 0

This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

3 0
3 years ago
Denise spent $56.48 at the grocery store while Michael spent $74.06. How much more money did Michael spendthan Denise?A.$17.58B.
ZanzabumX [31]
We will use the equation 74.06-56.48=? To find the change in prices, aka how much more money was spent. That equals 17.58. So A, Michael spent $17.58 more than Denise.
3 0
3 years ago
Read 3 more answers
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