Ànswer is A
Where h=-6 and k=-5whereh k vertex of a parabola
3(x-5)-4(x+3)
Multiply the first bracket by 3
(3)(x)=3x
(3)(-5)=-15
(-4)(x)=-4x
(-4)(3)=-12
3x-15-4x-12
3x-4x-15-12 ( combine like terms)
Answer: -x-27
For the first digit there are 7 choices. For the second digit there are 6 choices (because we can't use the same one again). And so on, until there is only one choice for the last digit.
The number of possible codes is this:
7*6*5*4*3*2*1 = 7! = 5040
