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3 years ago

One of the factors of 6x^2-5x-4 is (2x-1). What is the other factor?

Mathematics

1 answer:

kicyunya [14]3 years ago

3 0

Answer:

3x-4

Step-by-step explanation:

<em>The premise is incorrect</em>.

The factorization of 6x^2 -5x -4 is ...

... 6x^2 -5x -4 = (2x +1)(3x -4)

The factor that is not 2x+1 is 3x -4.

_____

If you were to assume the premise is correct, the x-term of the remaining factor is 6x^2/(2x) = 3x, and the constant term is (-4)/(-1) = +4, suggesting the correct answer to be 3x+4. As we have noted above, this is wrong.

(Have your teacher show you how to work this problem and check the answer.)

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A function is said to have a vertical asymptote wherever the limit on the left or right (or both) is either positive or negative

lubasha [3.4K]

$\lim_{x\to -2^-} \frac{-3(x+2)}{x^2+4x+4}
\\
\\ \text{Let}
\\
\\x=-2-h\ where\ h\to 0
\\
\\ \text{so} 
\\
\\\lim_{h\to 0} \frac{-3(-2-h+2)}{(-2-h)^2+4(-2-h)+4} =\lim_{h \to 0}\frac{-3\times -h}{4+h^2+4h-8-4h+4}
\\
\\ \text{We get}
\\
\\\lim_{h\to 0}\frac{3h}{h^2}=+\infty\Rightarrow P$

$\lim_{x\to -2^+} \frac{-3(x+2)}{x^2+4x+4}
\\
\\ \text{Let}
\\
\\x=-2+h\ where\ h\to 0
\\
\\ \text{so} 
\\
\\\lim_{h\to 0} \frac{-3(-2+h+2)}{(-2+h)^2+4(-2+h)+4} =\lim_{h \to 0}\frac{-3\times h}{4+h^2-4h-8+4h+4}
\\
\\ \text{We get}
\\
\\\lim_{h\to 0}\frac{-3h}{h^2}=-\infty\Rightarrow P$

$\lim_{x\to -2} \frac{-3(x+2)}{x^2+4x+4} =\frac{-3(-2+2)}{(-2)^2+4(-2)+4} = \frac{-3\times0}{0} = \frac{-0}{0} \Rightarrow D$

7 0

3 years ago

Pls help asap ill give brainliest!

dedylja [7]

<h3>Answer</h3>

$3 \times (x + 4) = 3x + 11$

$3x + 12 = 3x + 11$

That's impossible, cause 3x plus 12 can't be equal to 3x plus 11.

3 0

3 years ago

Read 2 more answers

Please help me solve this

Minchanka [31]

Answer:

Step-by-step explanation:

Sean buys some T-shirts for $12 each and the same number of belts for $7.50 each. Write an expression in the simplest form that represents the total amount.

So n represents the same number for t-shirts and belts.

Therefore n x 12.50 + n x 7.50 OR n(12.50+7.50)

The problem the student made was that they multiplied 12 times n plus 7.50. They forgot to multiply n times 7.50.

An expression that represents the total amount spent is 12n + 7.50n

Hope this helps!

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3 years ago

What is the area of the triangle

Reika [66]

Base x height divided by 2
10x8=80
80÷2=40
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3 years ago

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inysia [295]

Answer:

Step-by-step explanation:

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