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3 years ago

Suppose f(x) = x2 and g(x) = 2x − 3. What is the value of g(4) + f(−3)?

Mathematics

1 answer:

MAVERICK [17]3 years ago

8 0

In order to find the value of g(4)+f(-3), we must substitute those values into the functions first.

Substitute -3 into f(x).

f(x)=x²

f(-3)=(-3)²

f(-3)=9

Substitute 4 into g(x).

g(x)=2x-3

g(4)=2(4)-3

Using the rules of PEMDAS, multiply first then subtract.

g(4)=8-3

g(4)=5

Therefore, if f(-3) is 9 and g(4) is 5, we must add the two values together.

5+9=14

The value of g(4)+f(-3) is 14.

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Answer:

$x = \sqrt{2} - 8\\x = -\sqrt{2} - 8$

Step-by-step explanation:

To complete the square, we first have to get our equation into $ax^2 + bx = c$ form.

First we add 16x to both sides:

$x^2 + 16x + 62 = 0$

And now we subtract 62 from both sides.

$x^2 + 16x = -62$

We now have to add $(\frac{b}{2})^2$ to both sides of the equation. b is 16, so this value becomes $(16\div2)^2 = 8^2 = 64$ .

$x^2 + 16x + 64 = -62+64$

We can now write the left side of the equation as a perfect square. We know that x+8 will be the solution because $8\cdot8=64$ and $8+8=16$ .

$(x+8)^2 = -62 + 64$

We can now take the square root of both sides.

$x+8 = \sqrt{-62+64}\\\\ x+8 = \pm \sqrt{2}$

We can now isolate x on one side by subtracting 8 from both sides.

$x = \pm\sqrt{2} - 8$

So our solutions are

$x = \sqrt{2} - 8\\x = -\sqrt{2} - 8$

Hope this helped!

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