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bulgar [2K]
2 years ago
6

These cones are similar. Find the volume

Mathematics
2 answers:
Serga [27]2 years ago
6 0

Answer:

the answer is 44cm3

Step-by-step explanation:

you're welcome

BARSIC [14]2 years ago
4 0
The correct answer is 3 centimeters of volume
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A botanist wishes to estimate the mean number of seeds for a certain fruit. She samples 11 specimens and finds the average numbe
Aliun [14]

Answer:

a)The 98% of confidence intervals are

Lower bound of CI = 47 -3.82436 = 43.1756

Upper bound of CI = 47 + 3.82436 = 50.8243

b) The conditions are required for the validity of the interval

A) μ known

Step-by-step explanation:

<u>Explanation</u>:-

The given sample size is 'n' =11

Given the average number of seeds is 47 with a standard deviation of 7

Sample mean (x⁻) = 47

Standard deviation (S) = 7

<u>The 98% of confidence intervals are</u>

(x^{-} - t_{0.02} \frac{S}{\sqrt{n} } , x^{-} + t_{0.02}\frac{S}{\sqrt{n} } )

(47 - t_{0.02} \frac{7}{\sqrt{11} } , 47+ t_{0.02}\frac{7}{\sqrt{11} } )

The degrees of freedom = n-1 =11-1 =10

t₀.₀₂= 1.812 ( from t - table)

now the intervals are

(47 - 1.812 \frac{7}{\sqrt{11} } , 47+ 1.812\frac{7}{\sqrt{11} } )

<u>Lower bound of CI = 47 -3.82436 = 43.1756</u>

<u>Upper bound of CI = 47 + 3.82436 = 50.8243</u>

The conditions are required for the validity of the interval

<u>A) μ known</u>

<u>Explanation</u>:-

If a random sample xi of size 'n' has been drawn from a normal population with a specified mean (μ) known.

The limit for  (μ)  is given by

(x^{-} - t_{0.02} \frac{S}{\sqrt{n} } , x^{-} + t_{0.02}\frac{S}{\sqrt{n} } )

5 0
3 years ago
20/20
BabaBlast [244]

Answer:

22 with 5$ left over

Step-by-step explanation:

do 300 - 75 then divide by 10

4 0
3 years ago
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