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galben [10]
3 years ago
9

Solve this simultaneous equation x+2y=11 x-2y=1

Mathematics
2 answers:
lana [24]3 years ago
7 0

Answer:

Equation 1,

x + 2y = 11

Equation 2,

x - 2y = 11

Take equation number 2.

x  -  2y = 11 \\ x = 11  +  2y

Substitute 'x' in Equation number 1.

x + 2y = 11 \\ 11 + 2y + 2y = 11 \\ 11 + 4y = 11 \\ 4y = 11 - 11 \\ 4y = 0 \\ y =  \frac{0}{4}  \\ y = 0

<u>y = 0.</u>

So x,

x = 11 - 2y \\ x = 11 - 2(0) \\ x = 11 - 0 \\ x = 11

<u>x = 11.</u>

Olegator [25]3 years ago
6 0

Answer:

using elimination method multiply both equations by 2...then subtract equation 2 from 1

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11.1.30<br> How many three-digit even numbers are possible if the leftmost digit cannot be zero?
Ann [662]

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Step-by-step explanation:

Step 1 :

We need to determine the  number of 3 digit numbers which is even and the leftmost digit is not zero .

The  3 digits with left most digit not equal to zero starts from 100 and goes up to 998

If we consider only the even 3 digit numbers in this interval, this would form an arithmetic progression with the first number a = 100 and the common difference d = 2.

Step 2:

The last number l  in this series is 998 .

So we have

a = 100

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d = 2

The nth term in the arithmetic progression is given by a + (n-1) d

so substituting the above values we get

100 + (n-1) 2 = 998

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Step 3 :

Answer :

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Anna71 [15]

Answer:

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Step-by-step explanation:

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