So... hmm bear in mind, when the boat goes upstream, it goes against the stream, so, if the boat has speed rate of say "b", and the stream has a rate of "r", then the speed going up is b - r, the boat's rate minus the streams, because the stream is subtracting speed as it goes up
going downstream is a bit different, the stream speed is "added" to boat's
so the boat is really going faster, is going b + r
notice, the distance is the same, upstream as well as downstream
thus
![\bf \begin{cases} b=\textit{rate of the boat}\\ r=\textit{rate of the river} \end{cases}\qquad thus \\\\\\ \begin{array}{lccclll} &distance&rate&time(hrs)\\ &----&----&----\\ upstream&48&b-r&4\\ downstream&48&b+4&3 \end{array} \\\\\\ \begin{cases} 48=(b-r)(4)\to 48=4b-4r\\\\ \frac{48-4b}{-4}=r\\ --------------\\ 48=(b+r)(3)\\ -----------------------------\\\\ thus\\\\ 48=\left[ b+\left(\boxed{\frac{48-4b}{-4}}\right) \right] (3) \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%0Ab%3D%5Ctextit%7Brate%20of%20the%20boat%7D%5C%5C%0Ar%3D%5Ctextit%7Brate%20of%20the%20river%7D%0A%5Cend%7Bcases%7D%5Cqquad%20thus%0A%5C%5C%5C%5C%5C%5C%0A%0A%5Cbegin%7Barray%7D%7Blccclll%7D%0A%26distance%26rate%26time%28hrs%29%5C%5C%0A%26----%26----%26----%5C%5C%0Aupstream%2648%26b-r%264%5C%5C%0Adownstream%2648%26b%2B4%263%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%0A%5Cbegin%7Bcases%7D%0A48%3D%28b-r%29%284%29%5Cto%2048%3D4b-4r%5C%5C%5C%5C%0A%5Cfrac%7B48-4b%7D%7B-4%7D%3Dr%5C%5C%0A--------------%5C%5C%0A48%3D%28b%2Br%29%283%29%5C%5C%0A-----------------------------%5C%5C%5C%5C%0Athus%5C%5C%5C%5C%0A48%3D%5Cleft%5B%20b%2B%5Cleft%28%5Cboxed%7B%5Cfrac%7B48-4b%7D%7B-4%7D%7D%5Cright%29%20%5Cright%5D%20%283%29%0A%5Cend%7Bcases%7D)
solve for "r", to see what the stream's rate is
what about the boat's? well, just plug the value for "r" on either equation and solve for "b"
The first sentence is irrelevant information, you can ignore that!
There are 20 players. Each player paid the <em>same amount. </em>
In total, they payed $500,000.
We need x, the amount a single player pays. x times 20 will give us 500,000. This gives us the equation 20x=500,000
Divide both sides by 20 to isolate the variable.
x=25,000
Answer:
The value of the digit 6 in 23,640 is ? Times ? Than the value of the 6 in 167892
Answer:
(a) 
(b) 
(c) Answer of part a is equation of line which is parallel to y axis and in part by equation of line is which is parallel to x axis
Step-by-step explanation:
We have given points are 
(a) Equation of line is given x = -9
We have to find the equation of line parallel to x= -9 and passing through
x = -9 line is parallel to y axis and so slope will be infinite
Equation of line is given by 
So 
(b) Equation of line is given 
This line is parallel to x axis so slope will be zero
So equation of line will be 
(c) Answer of part a is equation of line which is parallel to y axis and in part by equation of line is which is parallel to x axis
Those two numbers can't be directly added as long as they're in
radical form. The only way to add them is to find both square roots,
and then add those.
Another twist is the fact that every number has two square roots ...
one positive and the other negative. So there are four possible sums
of (√3 + √4) .
√3 = + or - 1.732051 (rounded)
√4 = + or - 2 (exactly)
The four sums are:
(+1.73205) + (+2) = <em>3.732 </em>(rounded)
(+1.73205) + (-2) = <em>-0.268</em> (rounded)
(-1.73205) + (+2) = <em>+0.268</em> (rounded)
(-1.73205) + (-2) = <em>-3.732</em> (rounded)
