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Sergeeva-Olga [200]
2 years ago
8

Mark made a business trip of 259.5 miles. He averaged 59mph for the first part of the trip and 57mph for the second part. If the

trip took 4.5 hours, how long did he travel at each rate?
Mathematics
1 answer:
max2010maxim [7]2 years ago
8 0

Answer:

Step-by-step explanation:

d = r * t

Let the time at 59 miles /  hour be t

59*t + 57* (4.5 - t) = 259.5              Remove the brackets

59*t + 256.5 - 57*t = 259.5            Combine the left

2t + 256.5 = 259.5                         Subtract 228 from both sides

2t = 259.5 - 256.5                          Combine

2t =  3                                              Divide by 2

t = 1.5

So he spent 1.5 hours going at 59 miles per hour

He spent 4.5 - 1.5 = 3 hours going 57 miles per hour.

                               

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What is the range and domain of (-3,-22) (-2,-8) (-1,2) (0,8)) (1,10) (2,8) (3,2)​
BartSMP [9]

Answer:

Step-by-step explanation:

domain is x component so

domain = {-3 , -2 , -1 , 0 , 1 , 2 , 3 }

range is y component so

range = { -22 , -8 , 2 , 8 , 10 , 2 }

note : repeated element can be written only one time. For eg here in range 8 is 2 times but we can write only one time because it is the rule for lisying range and domain.

3 0
3 years ago
The Candela brothers own two pizza restaurants, one on Park Street and one on Bridge Road.
koban [17]

The mean, median and mode are measures of central tendency, that is they tend to indicate the location middle of the data

Required values;

(a) The performance for the week for Park Street

  • Revenue is <u>Q₂ < $7,500 < Q₃</u>
  • The sales for the week is better than <u>72.91%</u> of all sales

The performance for the week for Bridge Road

  • Revenue; <u>Q₂ < $7,100 < Q₃</u>
  • The sale for the week is better than <u>59.87%</u> of all sales

(b) The mean is <u>$3611</u>

The median is $<u>3,600</u>

The standard deviation is $<u>3250</u>

The Interquartile range is $<u>6075</u>

Reason:

The table of values that maybe used to find a solution to the question is given as follows;

\begin{array}{|l|l|l|}\mathbf{Variable} &\mathbf{Park}&\mathbf{Bridge}\\N&36&40\\Mean&6611&5989\\SE \ Mean&597&299\\StDev&3580&1794\\Minimum&800&1800\\Q_1&3600&5225\\Median&6600&6000\\Q_3&9675&7625\\Maximum&14100&8600\end{array}\right]

(a) Park Street revenue = $7,500

Bridge Road's revenue = $7,100

The two stores sold close to but below the 75th percentile

Bridge Road revenue;

The z-score is given as follows;

Z = \dfrac{x - \mu }{\sigma }

  • Z = \dfrac{7100 - 5,989 }{1794 } \approx 0.6193

From the Z-Table, we have;

The percentile= 0.7291

  • Therefore, the sale for the week for Park Street is better than <u>72.91%</u> of all the sales

Park Street revenue;

The z-score is given as follows;

  • Z = \dfrac{7500 - 6611}{3580} \approx 0.25

From the Z-Table, we have;

The percentile = <u>0.5987</u>

  • Therefore, the sale for the week is better than <u>59.87 %</u> of all the sales

(b) Given that the operating cost is $3,000, frim which we have;

The subtracted value is subtracted from the mean and median to find the new value

Profit = The revenue - Cost

New mean = 6611 - 3000 = 3611

  • The new mean = <u>$3,611</u>

The new median = 6600 - 3000 = 3600

  • The new median = <u>$3,600</u>

The standard deviation and the interquartile range remain the same, therefore, we have;

  • The standard deviation = <u>$3,580</u>

The interquartile range = 9675 - 3600 = 6075

  • The interquartile range = <u>6075</u>

Learn more here:

brainly.com/question/21133077

brainly.com/question/23305909

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Answer:

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Step-by-step explanation:

6+3/34 =207/34

and 207/34+21/2=282/17

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Answer:

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