What is the Bernoulli formula?

Which process must first take place in order for the proteins in foods to be used by body cells?

barxatty [35]

Answer:

Digestion

1 is correct since you need to eat something before anything else.

2 is incorrect since if this was first, what are you storing?

3 is incorrect since that is the second thing you need to do.

4 is incorrect since that is the last thing to do.

5 0

3 years ago

Air enters a compressor operating at steady state at 1.05 bar, 300 K, with a volumetric flow rate of 21 m3/min and exits at 12 b

omeli [17]

Answer:

- 46.5171kW

Explanation:

FIrst, the value given:

P1 = 1.05 bar (Initial pressure)

P2 = 12 bar (final pressure)

Heat transfer, Q = - 3.5 kW (It is negative because the compressor losses heat to the surroundings)

Mgaseous nitrogen = Mair = 28.0134 Kg/mol (constant)

Universal gas constant, Ru = 8.3143 Kj/Kgmolk

Specific gas constant, R = 0.28699 Kj/KgK

Initial temperature, T1 = 300 K

Final temperature, T2 = 400 K

Finding the volume:

P1V1 = RT1

V1 = RT1 ÷ P1

= (0.28699 Kj/KgK X 300k) ÷ 105

Note convert bar to Kj/Nm by multiply it by 100

V1 = 0.81997 m3/Kg

To get the mass flow rate:

m = volumetric flow rate / V1

= (21 m3/min x 1/60seconds) ÷ 0.81997 m3/Kg

= 0.4268Kg/s

Using tables for the enthalpy,

hT1 = 300.19 KJ/Kg

hT2 = 400.98 KJ/Kg

The enthalpy change = hT2 - hT1

= 100.79 KJ/Kg

Power, P = Q - (m X enthalpy change)

= - 3.5 - (0.4268 X 100.79)

= - 46.5171kW

3 0

3 years ago

An AC power generator produces 50 A (rms) at 3600 V. The voltage is stepped up to 100 000 V by an ideal transformer and the ener

RSB [31]

Given:

$I_{rms} = 50 A$

voltage, V = 3600V

step-up voltage, V' = 100000 V

Resistance of line, $R = 100\ohm$

Solution:

To calculate % heat loss in long distance power line:

Power produced by AC generator, P = $50\times 3600$ W

P = 180000 W = 180 kW

At step-up voltage, V = 100000V or 100 kV

current, I = $\frac{P}{V'}$

I = $\frac{1800000}{100000}$

I = 1.8 A

Power line voltage drop is given by:

$V_{drop} = I\times R$

$V_{drop} = 1.8\times 100$

$V_{drop} = 180 V$

Power dissipated in long transmission line $P_{dissipated} = V_{drop}\times I$

Power dissipated in long transmission line $P_{dissipated} = 180\times 1.8$ = 324 W

% Heat loss in power line, $P_{loss} = \frac{P_{dissipated}}{P}\times 100$

% Heat loss in power line, $P_{loss} = \frac{324}{180000}\times 100$

$P_{loss} = 0.18%$

5 0

3 years ago

Question 1 : Replacement [42 Pts] Consider the following page reference string:

MakcuM [25]

Answer:

Optimal

Time 123456789101112

RS. ecbeagdcegda

F0. eeeeeeeee e e a

F1 c c c c c c c c c c c

F2 b b b g g g g g g g

F3 a a d d d d d d

Page fault? * * * * * * *

Total page fault:7

2. LRU

Time 1 2 3 4 5 6 7 8 9 10 11 12

RS e c b e a g d c e g d a

F0 e e e e e e e c c c c a

F1 c c c c g g g g g g g

F2 b b b b d d d d d d

F3 a a a a e e e e

Page fault? Y Y Y N Y Y Y Y Y N N Y Total page fault:9

3. LRU approximation algorithm: Second chance

Time 1 2 3 4 5 6 7 8 9 10 11 12

RS e c b e a g d c e g d a

F0 0,e 0,e 0,e 1,e 1,e 0,e 0,e 0,e 1,e 1,e 1,e 0,e

F1 0,c 0,c 0,c 0,c 0,g 0,g 0,g 0,g 1,g 1,g 0,g

F20,b0,b0,b0,b0,d0,d0,d0,d1,d0,dF30,a0,a0,a0,c0,c0,c0,c0,a

Page fault? YYYNYYYYNNNY

Total page fault: 8

4 0

3 years ago

Read 2 more answers

A ½-hp motor requires 120 volts. What amperage is required?

Zolol [24]

Answer:

3.11 A

Explanation:

Use the given relations between power, horsepower, voltage, and current to find the current requirement for the motor.

P = hp(745.7 W) = (1/2)(745.7 W) = 372.85 W

I = P/V = (372.85 W)/(120 V) = 3.1071 A

The amperage required is about 3.11 A.

5 0

3 years ago