The load is placed at distance 0.4 L from the end of
area.
<h3>What is meant by torque?</h3>
The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction. A vector quantity is torque.
Let the beam is of length L
Now the stress on both the end is the same now we can say that torque on the beam due to two forces must be zero
![$N_1 * x=N_2 *(L-x)$](https://tex.z-dn.net/?f=%24N_1%20%2A%20x%3DN_2%20%2A%28L-x%29%24)
also, we know that stress at both ends are same
![$\frac{N_1}{12}=\frac{N_2}{8}$](https://tex.z-dn.net/?f=%24%5Cfrac%7BN_1%7D%7B12%7D%3D%5Cfrac%7BN_2%7D%7B8%7D%24)
![$2 * N_1=3 * N_2$](https://tex.z-dn.net/?f=%242%20%2A%20N_1%3D3%20%2A%20N_2%24)
Now from two equations we have
![$\frac{3}{2} N_2 * x=N_2 *(L-x)](https://tex.z-dn.net/?f=%24%5Cfrac%7B3%7D%7B2%7D%20N_2%20%2A%20x%3DN_2%20%2A%28L-x%29)
solving the above equation we have
![$x=\frac{2}{5} L](https://tex.z-dn.net/?f=%24x%3D%5Cfrac%7B2%7D%7B5%7D%20L)
so the load is placed at distance 0.4 L from the end of
area.
The complete question is:
47. the beam is supported by two rods ab and cd that have cross-sectional areas of
and
, respectively. determine the position d of the 6-kn load so that the average normal stress in each rod is the same.
To learn more about torque refer to:
brainly.com/question/20691242
#SPJ4
Answer:
(a) Increases
(b) Increases
(c) Increases
(d) Increases
(e) Decreases
Explanation:
The tensile modulus of a semi-crystalline polymer depends on the given factors as:
(a) Molecular Weight:
It increases with the increase in the molecular weight of the polymer.
(b) Degree of crystallinity:
Tensile strength of the semi-crystalline polymer increases with the increase in the degree of crystallinity of the polymer.
(c) Deformation by drawing:
The deformation by drawing in the polymer results in the finely oriented chain structure of the polymer with the greater inter chain secondary bonding structure resulting in the increase in the tensile strength of the polymer.
(d) Annealing of an undeformed material:
This also results in an increase in the tensile strength of the material.
(e) Annealing of a drawn material:
A semi crystalline material which is drawn when annealed results in the decreased tensile strength of the material.
Answer and Explanation:
The answer is attached below
Answer:
a)
, b) ![\dot Q_{H} = 26.875\,kW](https://tex.z-dn.net/?f=%5Cdot%20Q_%7BH%7D%20%3D%2026.875%5C%2CkW)
Explanation:
a) The Coefficient of Performance of the Carnot Heat Pump is:
![COP_{HP} = \frac{T_{H}}{T_{H}-T_{L}}](https://tex.z-dn.net/?f=COP_%7BHP%7D%20%3D%20%5Cfrac%7BT_%7BH%7D%7D%7BT_%7BH%7D-T_%7BL%7D%7D)
After some algebraic handling, the temperature of the cold reservoir is determined:
![T_{H}-T_{L} = \frac{T_{H}}{COP_{HP}}](https://tex.z-dn.net/?f=T_%7BH%7D-T_%7BL%7D%20%3D%20%5Cfrac%7BT_%7BH%7D%7D%7BCOP_%7BHP%7D%7D)
![T_{L} = T_{H}\cdot \left(1-\frac{1}{COP_{HP}} \right)](https://tex.z-dn.net/?f=T_%7BL%7D%20%3D%20T_%7BH%7D%5Ccdot%20%5Cleft%281-%5Cfrac%7B1%7D%7BCOP_%7BHP%7D%7D%20%20%5Cright%29)
![T_{L} = (297.15\,K)\cdot \left(1-\frac{1}{12.5}\right)](https://tex.z-dn.net/?f=T_%7BL%7D%20%3D%20%28297.15%5C%2CK%29%5Ccdot%20%5Cleft%281-%5Cfrac%7B1%7D%7B12.5%7D%5Cright%29)
![T_{L} = 273.378\,K\,(0.228\,^{\textdegree}C)](https://tex.z-dn.net/?f=T_%7BL%7D%20%3D%20273.378%5C%2CK%5C%2C%280.228%5C%2C%5E%7B%5Ctextdegree%7DC%29)
b) The heating load provided by the heat pump is:
![\dot Q_{H} = COP_{HP}\cdot \dot W](https://tex.z-dn.net/?f=%5Cdot%20Q_%7BH%7D%20%3D%20COP_%7BHP%7D%5Ccdot%20%5Cdot%20W)
![\dot Q_{H} = (12.5)\cdot (2.15\,kW)](https://tex.z-dn.net/?f=%5Cdot%20Q_%7BH%7D%20%3D%20%2812.5%29%5Ccdot%20%282.15%5C%2CkW%29)
![\dot Q_{H} = 26.875\,kW](https://tex.z-dn.net/?f=%5Cdot%20Q_%7BH%7D%20%3D%2026.875%5C%2CkW)