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3 years ago

Which process must first take place in order for the proteins in foods to be used by body cells?

Engineering

1 answer:

barxatty [35]3 years ago

5 0

Answer:

Digestion

1 is correct since you need to eat something before anything else.

2 is incorrect since if this was first, what are you storing?

3 is incorrect since that is the second thing you need to do.

4 is incorrect since that is the last thing to do.

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Everyone has only one learning style. True or false? hurry pleasle this exp carees class

Temka [501]

Answer:

This is False because people can have more than 1

7 0

3 years ago

A 4-kW electric heater runs for 2 hours to raise the room temperature to the desired level. Determine the amount of electric ene

Anna35 [415]

Answer:

Q' = 8 KW.h

Q'=28800 KJ

Explanation:

Given that

Heat Q= 4 KW

time ,t = 2 hours

The amount of energy used in KWh given as

Q ' = Q x t

Q' = 4 x 2 KW.h

Q' = 8 KW.h

We know that

1 h = 60 min = 60 x 60 s = 3600 s

We know that W = 1 J/s

The amount of energy used in KJ given as

Q' = 8 x 3600 = 28800 KJ

Therefore

Q' = 8 KW.h

Q'=28800 KJ

6 0

3 years ago

Exercise 5.46 computes the standard deviation of numbers. This exercise uses a different but equivalent formula to compute the s

ruslelena [56]

Answer:

// This program is written in Java Programming Language

// Comments are used for explanatory purpose

// Program starts here

import java.util.Scanner;

public class STDeviation {

// Declare and Initialise size of Numbers to be 10

int Numsize = 10;

public static void main(String args [] ) {

Scanner scnr = new Scanner(System.in);

// Declare digits as double

double[] digits = new double[Numsize];

System.out.print("Enter " + Numsize + " digits: ");

// Input digits using iteration

for (int i = 0; i < digits.length; i++)

{

digits[i] = scnr.nextDouble();

}

// Calculate and Print Mean/Average

System.out.print("Average: " + mean(digits)+'\n');

// Calculate and Print Standard Deviation

System.out.println("Standard Deviation: " + deviation(digits));

}

// Standard Deviation Module

public static double deviation(double[] x) {

double mean = mean(x);

// Declare and Initialise deviation to 0

double deviation = 0;

// Calculate deviation

for (int i = 0; i < x.length; i++) {

deviation += Math.pow(x[i] - mean, 2);

}

// Calculate length

int len = x.length - 1;

return Math.sqrt(deviation / len);

}

// Mean Module

public static double mean(double[] x) {

// Declare and Initialise total to 0

double total = 0;

// Calculate total

for (int i = 0; i < x.length; i++) {

total += x[i];

}

// Calculate length

int len = x.length;

// Mean = total/length

return total / len;

}

4 0

3 years ago

Air at 7 deg Celcius enters a turbojet engine at a rate of 16 kg/s and at a velocity of 300 m/s (relative to engine). Air is hea

Savatey [412]

To solve this problem we will start using the given temperature values and then transform them to the Kelvin scale. From there through the properties of the tables, described for the Air, we will find the entropy. With these three data we can perform energy balance and find the speed of the fluid at the exit, which will finally help us find the total force:

$V_i = 300m/s$

$T_1 = 7\°C = 280K$

$T_2 = 427\°C = 700K$

$\dot{m} 16kg/s$

$\dot{Q}_{in} = 15000kJ/s$

Using the tables for gas properties of air we can find the enthalpy in this two states, then

$T_1 = 280K \rightarrow h_1 = 280.13kJ/Kg\cdot K$

$T_2 = 700K \rightarrow h_2 = 713.27kJ/Kg\cdot K$

Applying energy equation to the entire engine we have that

$\frac{\dot{Q}_{in}}{\dot{m}}+h_1 +\frac{1}{2} V^2_{in} = h_2 + \frac{1}{2} V^2_{out}$

$\frac{15000}{16}*10^3+280.13*10^3+\frac{1}{2} 300^2 = 713.27*10^3+\frac{1}{2} V^2_{out}$

$V_{out} = 1048.198m/s$

Finally the force in terms of mass flow and velocity is

$F = \dot{m} (V_{out}-V_{in})$

$F = 16(1048.198-300)$

$F= 11971.168N$

Therefore the thrust produced by this turbojet engine is 11971.168N

4 0

3 years ago

Project 13.3: Assessing Risk Management According to the FFIEC Information Security InfoBase Handbook ( Appendix A ), the initia

Rashid [163]

Answer:

1. Changes in network topology or system configuration might bring security-related challenges. For example, adopting a new system configuration which is low in cost but also very new in the Industry might be vulnerable to the existing security.

2. New products or Services which are delivered to either the Internal/External users might be prone to security issues.

Let say a product 'A' has been launched by a company 'X' and for testing purpose it has been given to the internal users. Now as this product 'A' is a product of 'X' itself it will be allowed to carry in the official premises and if some user tries to hack this product and can make the product potentially harmful w.r.t security.

3. Consider a scenario where there is a change in management & team, the team members which were thoroughly responsible for Security kinds of stuff are dissolved into different teams. Also new members are hired for the team. Now, since the new members will need some time to get adapted to the Business As Usual things there are high chances of a security level not maintained as it was earlier by the old guys. This could be due to undocumented things in the organization or due to lack of Knowledge Transfer to the new joinees.

5 0

3 years ago