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damaskus [11]
2 years ago
12

a vertical cylindrical container is being cooled in ambient air at 25 °C with no air circulation. if the initial temperature of

the container surface is 100 °C, compute the surface heat-transfer coefficient due to natural convection during the initial cooling period. the diameter of the container is 1m, and it is 2 m high

Engineering
2 answers:
Sloan [31]2 years ago
7 0

Answer:

the surface heat-transfer coefficient due to natural convection during the initial cooling period.  = 4.93 w/m²k

Explanation:

check attachement for answer explanation

Brilliant_brown [7]2 years ago
3 0

Answer:

Explanation:

Find attach solution

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An incompressible fluid flows between two infinite stationary parallel plates. The velocity profile is given by u=umaxðAy2 + By+
nexus9112 [7]

Answer:

the volume flow rate per unit depth is:

\frac{Q}{b} = \frac{2}{3} u_{max} h

the ratio is : \frac{V}{u_{max}}=\frac{2}{3}

Explanation:

From the question; the  equations of the velocities profile in the system are:

u = u_{max}(Ay^2+By+C)   ----- equation (1)

The above boundary condition can now be written as :

At y= 0; u =0           ----- (a)

At y = h; u =0            -----(b)

At y = \frac{h}{2} ; u = u_{max}     ------(c)

where ;

A,B and C are constant

h = distance between two plates

u = velocity

u_{max} = maximum velocity

y = measured distance upward from the lower plate

Replacing the boundary condition in (a) into equation (1) ; we have:

u = u_{max}(Ay^2+By+C) \\ \\ 0 = u_{max}(A*0+B*0+C) \\ \\ 0=u_{max}C \\ \\ C= 0

Replacing the boundary condition (b) in equation (1); we have:

u = u_{max}(Ay^2+By+C) \\ \\ 0 = u_{max}(A*h^2+B*h+C) \\ \\ 0 = Ah^2 +Bh + C \\ \\ 0 = Ah^2 +Bh + 0 \\ \\ Bh = - Ah^2 \\ \\ B = - Ah   \ \ \ \ \   --- (d)

Replacing the boundary condition (c) in equation (1); we have:

u = u_{max}(Ay^2+By+C) \\ \\ u_{max}= u_{max}(A*(\frac{h^2}{2})+B*\frac{h}{2}+C) \\ \\ 1 = \frac{Ah^2}{4} +B \frac{h}{2} + 0 \\ \\ 1 =  \frac{Ah^2}{4} + \frac{h}{2}(-Ah)  \\ \\ 1=  \frac{Ah^2}{4}  - \frac{Ah^2}{2}  \\ \\ 1 = \frac{Ah^2 - Ah^2}{4}  \\ \\ A = -\frac{4}{h^2}

replacing A = -\frac{4}{h^2} for A in (d); we get:

B = - ( -\frac{4}{h^2})hB = \frac{4}{h}

replacing the values of A, B and C into the velocity profile expression; we have:

u = u_{max}(Ay^2+By+C) \\ \\ u = u_{max} (-\frac{4}{h^2}y^2+\frac{4}{h}y)

To determine the volume flow rate; we have:

Q = AV \\ \\ Q= \int\limits^h_0 (u.bdy)

Replacing u_{max} (-\frac{4}{h^2}y^2+\frac{4}{h}y) \ for \ u

\frac{Q}{b} = \int\limits^h_0 u_{max}(-\frac{4}{h^2} y^2+\frac{4}{h}y)dy \\ \\  \frac{Q}{b} = u_{max}  \int\limits^h_0 (-\frac{4}{h^2} y^2+\frac{4}{h}y)dy \\ \\ \frac{Q}{b} = u_{max} (-\frac{-4}{h^2}\frac{y^3}{3} +\frac{4}{h}\frac{y^2}{y})^ ^ h}}__0  }} \\ \\ \frac{Q}{b} =u_{max} (-\frac{-4}{h^2}\frac{h^3}{3} +\frac{4}{h}\frac{h^2}{y})^ ^ h}}__0  }} \\ \\ \frac{Q}{b} = u_{max}(\frac{-4h}{3}+\frac{4h}2} ) \\ \\ \frac{Q}{b} = u_{max}(\frac{-8h+12h}{6}) \\ \\ \frac{Q}{b} =u_{max}(\frac{4h}{6})

\frac{Q}{b} = u_{max}(\frac{2h}{3}) \\ \\ \frac{Q}{b} = \frac{2}{3} u_{max} h

Thus; the volume flow rate per unit depth is:

\frac{Q}{b} = \frac{2}{3} u_{max} h

Consider the discharge ;

Q = VA

where :

A = bh

Q = Vbh

\frac{Q}{b}= Vh

Also;  \frac{Q}{b} = \frac{2}{3} u_{max} h

Then;

\frac{2}{3} u_{max} h = Vh \\ \\ \frac{V}{u_{max}}=\frac{2}{3}

Thus; the ratio is : \frac{V}{u_{max}}=\frac{2}{3}

5 0
3 years ago
On December 5, 2017, the Tursis defaulted on their promissory note to the Green Mountain Inn. On June 11, 2017, PP, Inc., former
leva [86]

Answer:

The note in this question is not an instrument that is negotiable under Article 3 of the U.C.C. Furthermore, it is not payable at any given time on demand due to the fact that principal repayment is not covered at a specified period of time. It shows that the acceleration clause is viable for the payment of the amount upon the default of the maker. This is also for an indefinite period of time.

Explanation:

The note in this question is not an instrument that is negotiable under Article 3 of the U.C.C. Furthermore, it is not payable at any given time on demand due to the fact that principal repayment is not covered at a specified period of time. It shows that the acceleration clause is viable for the payment of the amount upon the default of the maker. This is also for an indefinite period of time.

5 0
3 years ago
An industrial system is rated at 600 v the system includes a partially exposed terminal block thats mounted on a bulkhead a new
Nastasia [14]

Answer:

10 ft or 3.048 m (for unqualified person)

1.09 ft or 0.33 m (for qualified person)

Explanation:

OSHA has prescribed "Minimum Approach Distance - MAD" to ensure safety of personnel working with electrical power lines.

For a unqualified person:

The minimum approach distance is 10 ft or 3.048 m

For a qualified person:

For a voltage in the range of 300V to 750V (Phase to Ground or Phase to Phase) the minimum approach distance is 1.09 ft or 0.33 m

Since 600V lies in the above range hence it is applicable on 600V.

OSHA has developed a full list of minimum approach distance according to the level of voltages (50V to 72000V)

7 0
2 years ago
A motor whose pulley is 80mm in diameter is rotating at 30 revolutions per minute and is connected by a belt to another pulley o
Firdavs [7]

Answer:

169

Explanation:

ye men thats the answer

8 0
2 years ago
if you’re disassembling a master cylinder and the front piston assembly is stuck in the master cylinder you can
lianna [129]

Answer:

Put water in the cylinder then push the piston inward

Explanation:

When water is put it displaces all the air making it possible for the piston to be pulled easier and without distraction

6 0
3 years ago
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