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damaskus [11]
3 years ago
12

a vertical cylindrical container is being cooled in ambient air at 25 °C with no air circulation. if the initial temperature of

the container surface is 100 °C, compute the surface heat-transfer coefficient due to natural convection during the initial cooling period. the diameter of the container is 1m, and it is 2 m high

Engineering
2 answers:
Sloan [31]3 years ago
7 0

Answer:

the surface heat-transfer coefficient due to natural convection during the initial cooling period.  = 4.93 w/m²k

Explanation:

check attachement for answer explanation

Brilliant_brown [7]3 years ago
3 0

Answer:

Explanation:

Find attach solution

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\int\limits^1_2 {} \, dQ = \int\limits^1_2 {} \, dU + nRT \int\limits^1_2 {\frac{1}{V}} \, dV

Q_{2} - Q_{1} = U_{2} - U_{1} + nRT(ln V_{2} - ln V_{1})

Q_{2} - Q_{1} = U_{2} - U_{1} + nRT ln \frac{V_{2}}{V_{1}}

The internal energy depends only on the temperature of the gas, so there is no internal energy change U_{2} - U_{1} = 0, so the heat exchanged to the system equals the work done by the system:

Q_{in} = W_{out} = nRT ln (\frac{V_{2}}{V_{1}})

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