4 - 12 per hour. How many paners will that teacher review in 6-13 hours

I need help anyone can help me? I’ll mark ya braninly

Oksana_A [137]

Answer:

You are more likely to grab a red marble. You are less likely to grab a green marble.

Step-by-step explanation:

6/16 is greater than 5/16. The bigger the number, the higher the probability.

Have a great day!

5 0

3 years ago

Find the two intersection points

bogdanovich [222]

Answer:

Our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

Step-by-step explanation:

We want to find where the two graphs given by the equations:

$\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1$

Intersect.

When they intersect, their x- and y-values are equivalent. So, we can solve one equation for y and substitute it into the other and solve for x.

Since the linear equation is easier to solve, solve it for y:

$\displaystyle y = -\frac{3}{4} x + \frac{1}{4}$

Substitute this into the first equation:

$\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16$

Simplify:

$\displaystyle (x+1)^2 + \left(-\frac{3}{4} x + \frac{9}{4}\right)^2 = 16$

Square. We can use the perfect square trinomial pattern:

$\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16$

Multiply both sides by 16:

$(16x^2+32x+16)+(9x^2-54x+81) = 256$

Combine like terms:

$25x^2+-22x+97=256$

Isolate the equation:

$\displaystyle 25x^2 - 22x -159=0$

We can use the quadratic formula:

$\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a = 25, b = -22, and c = -159. Substitute:

$\displaystyle x = \frac{-(-22)\pm\sqrt{(-22)^2-4(25)(-159)}}{2(25)}$

Evaluate:

$\displaystyle \begin{aligned} x &= \frac{22\pm\sqrt{16384}}{50} \\ \\ &= \frac{22\pm 128}{50}\\ \\ &=\frac{11\pm 64}{25}\end{aligned}$

Hence, our two solutions are:

$\displaystyle x_1 = \frac{11+64}{25} = 3\text{ and } x_2 = \frac{11-64}{25} =-\frac{53}{25}$

We have our two x-coordinates.

To find the y-coordinates, we can simply substitute it into the linear equation and evaluate. Thus:

$\displaystyle y_1 = -\frac{3}{4}(3)+\frac{1}{4} = -2$

And:

$\displaystyle y _2 = -\frac{3}{4}\left(-\frac{53}{25}\right) +\frac{1}{4} = \frac{46}{25}$

Thus, our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

6 0

3 years ago

What is the slope of the line that passes through the points (-15,7) and (14,7)

gayaneshka [121]

The slope of the line that passes through the points (-15,7) and (14,7) is 0

6 0

2 years ago

Which of the following equations has no solution?

Ronch [10]

Answer:

B and D

Step-by-step explanation:

Equations with the same x- term on both sides will have no solution

A

4x - 13 = 5(x + 4) = 5x + 20

4x ≠ 5x

This equation has a solution

B

5(3 + 2x) = 10x + 4

15 + 10x = 10x + 4

10x on both sides ⇒ no solution

C

2(3 - 5x) = 8(x + 1)

6 - 10x = 8x + 8

- 10x ≠ 8x

This equation has a solution

D

9x - 6 = 3(3x - 2) = 9x - 6

9x on both sides ⇒ no solution

8 0

2 years ago

Can someone please help me

agasfer [191]

Answer:

See below

Step-by-step explanation:

If |x| < |y| and both are negative the x will be to the right of y on the number line. The point x is loser to the zero on the number line. We can illustrate this by supposing x = -3 and y = -6.

|x| = 3 and |y| = 6 and 3 < 6 but -3 on the number line is higher ( to the right) of -6 and closer to the zero.

|-8 1/3| = 8 1/3

|7 2/3| = 7 2/3

The absolute values of 8 1/3 > than absolute value of 7 2/3. The point 7 2/3 is closer to the zero on a number line.

The absolute value of F is greater than absolute value of E so E is closer to the zero line than F.

6 0

3 years ago