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Ratling [72]
3 years ago
11

F(x) = x^2 . What is g(x)​

Mathematics
1 answer:
viktelen [127]3 years ago
8 0
Answer- the letter b.
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Find the five arithmetic means between -18 and 36
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Estimate the probability that an Earthbound meteorite either disintegrates above or impacts with a body of water. Round to the n
Ad libitum [116K]

Answer:

0.71 is the answer

Step-by-step explanation:

Answered on edu

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3 years ago
Erin feeds her dog 7/10 cup of food a day . With 3/10 cup canned and the rest dry . She also gives her dog 1 treat a day . How m
gavmur [86]

Answer:

2\frac{4}{5}\ \ or \ 2.8 \ \ cups

Step-by-step explanation:

-The total portion fed to the dog is 7/10 cup

  • Canned-3/10
  • Dry=7/10-3/10=4/10

-One week has 7 days. we multiply the dry portion per day by the number of days in a week.

Dry= Total -Canned\\\\=\frac{7}{10}-\frac{3}{10}\\\\=0.40 \ cup\\\\Dry \ per \ Week= Dry/ day\times days\\\\=0.40\times 7\\\\=2\frac{4}{5}\  or\  2.8 \ cups

Hence, Erin feed her dog 2 4/5 0r 2.8 cups of dry food

5 0
3 years ago
The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or
tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}


P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67

Putting these values,

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%

5 0
3 years ago
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