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lora16 [44]
3 years ago
10

HELP WILL GIVE BRAINLEIST AND LOVE YOU FOREVER

Mathematics
1 answer:
jasenka [17]3 years ago
4 0
I think #3 is 20 and #4 is a trapezoid. im so sorry if that’s wrong. if it is lmk and ill try again.
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A pediatrician records the age (in months) and the height (in inches) of a baby over time and creates a scatter plot. Using the
creativ13 [48]

Answer:

Your answer would be C

Step-by-step explanation:

18 inches was the height of the baby when they were born since it isn't y which would be the current height of the baby now in months that tells me months have passed which includes x is the age of the baby in months.

8 0
3 years ago
PLEASE HELP ME I HAVE A SICKNESS CALLED IM DUMB AND I REALLY NEED HELP WITH THESE QUETIONS. IF YOU CAN ANSWER THEM ALL ILL GIVE
slava [35]

Step-by-step explanation:

the answer in the image

7 0
3 years ago
If y varies inversely as x, and y=12 when x=3 find y when x=4
aleksandrvk [35]
First find constant for inversely proportional k(constant)=12×3=36 so in next 36=y4..y=36/4=9
6 0
4 years ago
Law of cosines: a2 = b2 + c2 – 2bccos(A) Find the measure of J, the smallest angle in a triangle with sides measuring 11, 13, an
Andrej [43]
Given the sides 11,13,19, to calculate for the smallest angle using cosine rule, i.e;
a^2=b^2+c^2-2bc cos (A)

we shall proceed as follows;

The smallest angle is always opposite to the shortest side; Since 11 is our shortest side, the smallest angle is the angle opposite to this side. Thus;
let a=11 and our smallest  angle be A
thus
11^2=13^2+19^2-2*13*19 Cos A
121=169+361-494 Cos A
121=530-494 Cos A
-409=-494 Cos A
dividing through by -494 we get;
Cos A=0.8279

thus
A=Cos(-1) 0.8279
A=34.113°≈34°

The answer is A=34°

7 0
3 years ago
Read 2 more answers
Coordinates A (1, 2), B (3, 2) and C (3, 5) are connected to form ΔABC. If ΔDFE is similar to ΔABC, what are the coordinates of
vesna_86 [32]

Answer:

Possible coordinate of F are (10,5) and (6,11)

Step-by-step explanation:

Coordinates A (1, 2), B (3, 2) and C (3, 5) are connected to form ΔABC

First we plot the points on coordinate plane and then draw triangle ABC. Please see the attachment for figure.

If ΔDFE is similar to ΔABC then their corresponding sides are in proportional.

\therefore \frac{AB}{DF}=\frac{AC}{DE}=\frac{BC}{FE}

Using distance formula, d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AB=\sqrt{(3-1)^2+(2-2)^2}=\sqrt{4+0}=2

AC=\sqrt{(3-1)^2+(5-2)^2}=\sqrt{4+9}=\sqrt{13}

BC=\sqrt{(3-3)^2+(5-2)^2}=\sqrt{0+9}=3

DE=\sqrt{(10-6)^2+(11-5)^2}=\sqrt{16+36}=2\sqrt{13}

\frac{AC}{DE}=\frac{1}{2}

We can see  ABC is right angle triangle. So, DEF must be right angle triangle because ΔDFE ~ ΔABC

\frac{BC}{FE}=\frac{1}{2}=\frac{3}{6}

\therefore FE=6

\frac{AB}{DF}=\frac{1}{2}=\frac{2}{4}

\therefore DF=4

Thus, Possible coordinate of F are (10,5) and (6,11)

6 0
3 years ago
Read 2 more answers
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