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3 years ago

PLEASE GUYS IM DESPRATE

Mathematics

2 answers:

Nezavi [6.7K]3 years ago

8 0

Answer:

-11

Step-by-step explanation:

-(-3)-(2^3)+(-3)2

3-8-6=-11

VikaD [51]3 years ago

5 0

Answer:

Step-by-step explanation:

Putting values in the equation

-(-3)-(2)3+ (-2) (3)

3 - 8 + (- 6)

-5 - 6

= - 11

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What’s the evaluation to 5x(2) + x for x =3

Mashcka [7]

Answer:

Step-by-step explanation:

5 x^2 +x

Let x = 3

5 * 3^2 +3

Exponents first

5 * 9+3

Multiply next

45+3

5 0

3 years ago

Read 2 more answers

What are the solutions of the equation x4 + 95x2 – 500 = 0?

Ugo [173]

X4+(95x2)-500=0
x4+(190)-500=0
x4-310=0
x4=310
x=4√(310)
x=4.196

8 0

3 years ago

How do you solve it?

Elis [28]

At heart we're being asked for a line through two points,

$(40^\circ \textrm{ C}, 355 \textrm { m/s}) \quad \textrm{and} \quad (49^\circ \textrm{ C}, 360 \textrm { m/s})$

In general the line through (a,b) and (c,d) is

$(y-b)(c-a)=(x-a)(d-b)$

Check that you understand why both (a,b) and (c,d) are on this line.

Here our indepedent variable, instead of x, is T, temperature. Our dependent variable is v, velocity. Substituting,

$(v - 355)(49 - 40) = (T - 40)(360 - 355)$

$9(v - 355) = 5(T - 40)$

$v-355 = \frac 5 9 T - \frac{200}{9}$

$v= \frac 5 9 T - \frac{200}{9} + 355$

$v= \frac 5 9 T + \frac{2995}{9}$

That's our answer; let's check it.

When T=40, v = (5/9)40 + (2995/9) = 355 good

When T=49, v= (5/9)49 + (2995/9) = 360 good

7 0

2 years ago

Help with matrices please? Any wrong/not applicable answers will be reported and BLOCKED

marin [14]

m x H = $\left[\begin{array}{ccc}-25&37.5&-12.5\\\9\end{array}\right]$

Step-by-step explanation:

Step 1; Multiply 5 with this matrix $\left[\begin{array}{ccc}-1&2\\4&8\\\end{array}\right]$ and we get a matrix $\left[\begin{array}{ccc}-5&10\\20&40\\\end{array}\right]$

Multiply the fraction $\frac{2}{5}$ with the matrix $\left[\begin{array}{ccc}-1&2\\4&8\\\end{array}\right]$ and we get $\left[\begin{array}{ccc}-\frac{2m}{5} &\frac{4m}{5} \\\frac{8m}{5} &\frac{16m}{5} \\\end{array}\right]$

Step2; Now equate corresponding values of the matrices with each other.

-5 = $\frac{-2m}{5}$ and so on. By equating we get the value of m as $\frac{25}{2}$

Step 3; Add the matrices to get the value of matrix m.

Adding the three matrices on the RHS we get $\left[\begin{array}{ccc}2&9&-9\\\end{array}\right]$ .

Step 4; Adding the matrices on the LHS we get the resulting matrix as H +

$\left[\begin{array}{ccc}4&6&-8\\\9\end{array}\right]$ . Equating the matrices from step 3 and 4 we get the value of H as $\left[\begin{array}{ccc}-2&3&-1\\\9\end{array}\right]$

Step 5; Now to find the value of m x H we need to multiply the value of $\frac{25}{2}$ with the matrix $\left[\begin{array}{ccc}-2&3&-1\\\9\end{array}\right]$

Step 6; Multiplying we get the matrix m x H = [ -25 $\frac{75}{2}$ $\frac{-25}{2}$ ]