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blondinia [14]
3 years ago
7

WILL GIVE BRANLIEST!!! Pls help! Determine the coordinates of the point on the straight line y=3x+1 that is equidistant from the

origin and (−3, 4).
Mathematics
1 answer:
iren [92.7K]3 years ago
6 0

Let , coordinate of points are P( h,k ).

Also , k = 3h + 1

Distance of P from origin :

d=\sqrt{h^2+k^2}

Distance of P from ( -3, 4 ) :

d=\sqrt{(h+3)^2+(k-4)^2}

Now , these distance are equal :

h^2+(3h+1)^2=(h+3)^2+(3h+1-4)^2\\\\h^2+(3h+1)^2=(h+3)^2+(3h-3)^2

Solving above equation , we get :

P=(\dfrac{16}{21},\dfrac{23}{7})

Hence , this is the required solution.

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