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julia-pushkina [17]
3 years ago
8

Help pls

Mathematics
1 answer:
ki77a [65]3 years ago
3 0

Answer:

Distance between the school and the theater = 2\sqrt{13} units

Step-by-step explanation:

Use distance formula to calculate the distance from the school (8, 7) and the theater (2, 3):

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

school (8, 7) = (x_1, y_1)

theater (2, 3) = (x_2, y_2)

Plug in the values into the distance formula

d = \sqrt{(2 - 8)^2 + (3 - 7)^2}

d = \sqrt{(-6)^2 + (-4)^2}

d = \sqrt{36 + 16} = \sqrt{52}

Simplify

d = \sqrt{4 \times 13}

d = 2\sqrt{13}

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<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

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The mean and the standard deviation are given, respectively, by:

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The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:

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More can be learned about the normal distribution at brainly.com/question/27643290

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