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fomenos
3 years ago
15

Please help with these. I will give you brainlist

Mathematics
2 answers:
Nitella [24]3 years ago
6 0

Answer: 22 and 131

Step-by-step explanation:

ser-zykov [4K]3 years ago
5 0

Answer:

Step-by-step explanation:

3. slope of CB = rise/run = 5/12      BF = 5    CF = 12

BF ⊥ DF

DB (seg of two farthest points) = √BF²+DF² = √5²+32² = √1049 = 32.4

4. f(x) = 2x² - 5x -3      vertex : A (h,k)  for f(x) = ax² + bx +c

h = - b/2a = - (-5 / 4) = 5/4

f = f(h) = 2*(5/4)² - 5*(5/4) - 3 =25/8 - 25/4 -3 = -49/8

A (5/4 , - 49/8) i.e. (1.25 , - 6.13)

negative root:   2x² - 5x -3 = (2x+1) (x- 3)      x = - 1/2      y = 0

B (- 1/2 , 0)

x coordinate of AB: 1/2 (1.25 + -0.5) = 0.375

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write the standard form of the equation of the line described. through (-2,3), perpendicular to y=2/7x+5
Setler79 [48]
The general form of a linear equation is
y = mx + b
where m = slope and b = y-intercept
Here m = 2/7
To get to its perpendicular equation, first the slope should be negative reciprocal. So the perpendicular slope is m = -7/2
Given the point (-2,3), use the point-slope form equation, that is
y - y1 = m(x - x1)
Plug in
y - 3 = (-7/2)[x - (-2)]
y - 3 = (-7/2)x - 7
y = (-7/2)x - 7 + 3
y = (-7/2)x - 4
That is the equation required.
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