Answer:
Its B. Just look at google.
Hello! So to answer your question all the answers can be found within the above chart provided. Simply compare and contrast the pH levels in which the indicators changed color.
So doing that we can conclude the followoing pertaining to our indicators. Bromothymol blue 5.3-7.3
Methyl yellow 2.4-4.3
Bromocresol green 3.3-5.3
Red cabbage extract 3.3-5.3
For your second question it is the exact same concept, but we can just look at our answer for the first question to conclude which indicator would be best used for those ph levels.
Comparing and contrasting we can see that the best indicator to use for observing PH changes around pH= 2 would be Methyl yellow,
for around pH=4 would be Bromocrescol green,
and for pH= 6 it would be Bromothymol blue.
If you have any other questions or would like further explanation just let me know! :)
Answer:
Option (D)
Explanation:
Sedimentary rocks are those that are formed from the deposition, compaction, and lithification of loose and unconsolidated sediments. This includes Shale, Sandstone and Limestone.
These sedimentary rocks can be altered into metamorphic rock by allowing it to experience higher pressure and temperature conditions. This can be taken place by the burial of sedimentary rocks during the time of the continental collision, where the rocks subjected to high pressure and temperature due to the weight of the overlying condition. The sedimentary rock 'shale' turns into a metamorphic rock named 'slate' due to the process of metamorphism.
Thus, the correct answer is option (D).
Answer: a) Anode:
Cathode:
b) Anode : Cr
Cathode : Au
c)
d)
Explanation: -
a) The element Cr with negative reduction potential will lose electrons undergo oxidation and thus act as anode.The element Au with positive reduction potential will gain electrons undergo reduction and thus acts as cathode.
At cathode:
At anode:
b) At cathode which is a positive terminal, reduction occurs which is gain of electrons.
At anode which is a negative terminal, oxidation occurs which is loss of electrons.
Gold acts as cathode ad Chromium acts as anode.
c) Overall balanced equation:
At cathode: (1)
At anode: (2)
Adding (1) and (2)
d)= -0.74 V
= 1.40 V
Using Nernst equation :
where,
n = number of electrons in oxidation-reduction reaction = 3
= standard electrode potential = 2.14 V
Thus the standard potential for an electrochemical cell with the cell reaction is 2.14 V.
If the temperature of a liquid-vapor system at equilibrium increases, it will shift towards the vapor phase, assuming that the pressure remains equal. The concentration of vapor will also increase relative to the concentration of liquid in the system. Thus, the new equilibrium condition will have more vapor than liquid.