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Andre45 [30]
3 years ago
8

A car travels 140 miles in 3 hours. What is its velocity?

Physics
1 answer:
Maslowich3 years ago
3 0

Answer:

46.67 miles/s

Explanation:

...........

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Suppose that the voltage across the resistor is held constant at 40 volts. If the resistance is steadily decreasing at a rate of
hjlf

Answer:

The current is increasing at a rate of 0.32 ampere per second.

Explanation:

The voltage of the resistor is modelled after Ohm's Law, which states that voltage is directly proportional to current:

V = i\cdot R (1)

Where:

V - Voltage, measured in volts.

i - Current, measured in amperes.

R - Resistance, measured in ohms.

An expression for the rate of change in voltage is found by Differential Calculus:

\frac{dV}{dt} = \frac{di}{dt}\cdot R +i\cdot \frac{dR}{dt}

\frac{dV}{dt} = \frac{di}{dt}\cdot R + \frac{V}{R}\cdot \frac{dR}{dt} (2)

Where:

\frac{dV}{dt} - Rate of change in voltage, measured in volts per second.

\frac{di}{dt} - Rate of change in current, measured in amperes per second.

\frac{dR}{dt} - Rate of change in resistance, measured in ohms per second.

If we know that \frac{dV}{dt} = 0\,\frac{V}{s}, R = 5\,\Omega, V = 40\,\Omega and \frac{dR}{dt} = -0.2\,\frac{\Omega}{s}, then the rate of change in current is:

5\cdot \frac{di}{dt}-1.6 = 0 (3)

\frac{di}{dt} = 0.32\,\frac{A}{s}

The current is increasing at a rate of 0.32 ampere per second.

5 0
3 years ago
What is the heat source for rock formation​
Otrada [13]

Answer:

Explanation:

The heat source for rock formation

Primordial heat: Some heat accumulated during the earth's formation and it is still available to drive the internal heat Engine of the earth. Some of these heat are used to melt rocks and produce magma.

Radioactive sources: Radioactive elements within the earth also serves as heat source for rock formation. Their spontaneous decay produce heat which are sufficient enough to generate enough thermal energy to melt and produce rocks.

6 0
4 years ago
A soapbox derby is to be held on a frictionless hill with a 28 m vertical drop. The track is 300 m long. What is
ki77a [65]

Answer: -31039 J

Explanation:

5 0
3 years ago
An 18-cm-long bicycle crank arm, with a pedal at one end, is attached to a 20-cm-diameter sprocket, the toothed disk around whic
Tpy6a [65]

Answer:

Part a)

a = 0.056 m/s^2

Part b)

L = 7.85 m

Explanation:

Part a)

Angular speed of the pedal is changing from 60 rpm to 90 rpm in 10 s

so the angular acceleration is given as

\alpha = \frac{\omega_2 - \omega_1}{\Delta t}

so we will have

\alpha = \frac{2\pi(\frac{90}{60}) - 2\pi(\frac{60}{60})}{10}

\alpha = 0.314 rad/s^2

now the tangential acceleration of the pedal is given as

a = r \alpha

a = 0.18 \times 0.314

a = 0.056 m/s^2

Part b)

Total angular displacement made by the sprocket in the interval of 10 s is given as

\theta = \frac{\omega_f + \omega_i}{2} t

\theta = \frac{2\pi (\frac{90}{60}) + 2\pi (\frac{60}{60})}{2}(10)

\theta = 78.5 radian

now length of the chain passing over it is given as

L = R\theta

L = 0.10 \times 78.5

L = 7.85 m

6 0
4 years ago
A 12cm candle is placed 6cm from a converging lens with a focal length of 15cm. What is the height of the image of the candle? S
amm1812

Answer:

The height of the image of the candle is 20 cm.

Explanation:

Given that,

Size of the candle, h = 12 cm

Object distance from the candle, u = -6 cm

Focal length of converging lens, f = 15 cm

To find,

The height of the image of the candle.

Solution,

Firstly, we will find the image distance of the candle. Let it is equal to v. Using lens formula to find the image distance.

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

v is image distance

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-6)}\\\\v=-10\ cm

If h' is the height of the image. Magnification is given by :

m=\dfrac{h'}{h}=\dfrac{v}{u}

h'=\dfrac{vh}{u}\\\\h'=\dfrac{-10\times 12}{-6}\\\\h'=20\ cm

So, the height of the image of the candle is 20 cm.

3 0
3 years ago
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