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3 years ago

If f(x) = 3x - 1 and g(x) = x + 2, find (f+g)(x).

Mathematics

2 answers:

MatroZZZ [7]3 years ago

6 0

<h3>Given:</h3>

f(x) = 3x - 1

g(x) = x + 2

(f+g)(x) = f(x) + g(x)

<h3>Explanation:</h3>

By putting the values, we get

3x - 1 + x + 2

By simplifying the like terms, we get

3x + x - 1 + 2

= 4x + 1

<h2>Answer:</h2>

(f+g)(x) = 4x + 1

Therefore, <u>A</u><u>.</u><u> </u><u>4</u><u>x</u><u> </u><u>+</u><u> </u><u>1</u> is the correct answer.

kirill115 [55]3 years ago

4 0

Answer:

$\boxed {\boxed {\sf A. \ 4x+1}}$

Step-by-step explanation:

We are asked to find (f+g)(x). The question is essentially asking us to find the sum of f(x) and g(x).

$(f+g)(x)=f(x)+g(x)$

We know that f(x) equals 3x-1 and g(x) equals x+2. Substitute the values of the functions in.

$(f+g)(x)=(3x-1)+(x+2)$

Combine the like terms.

3x and x are like terms (both have the variable "x"
-1 and 2 are like terms (both without variables, also known as constants)

$(f+g)(x)=(3x+x)+(-1+2)$

$(f+g)(x)=(4x)+(1)=4x+1$

(f+g)(x) is equal to <u>4x+1</u> and the correct answer is A.

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3 years ago

The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi

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Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

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The volume is decreasing at a constant rate.

$\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}$

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Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

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Instant volume =

$525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}$

Differentiating with respect to t,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)$

Putting all the values, we get,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131$

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3 years ago

When simplified completely, the product of a monomial and a monomial is sometimesalwaysnever a monomial

Vaselesa [24]

Answer:

Always

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3 years ago

the seed and skin of a typical avacado is about 30%-40% of the avocados weight. for an 8-ounce avocado, how many ounces of edibl

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Answer:

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Step-by-step explanation:

Given as

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