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Nataly_w [17]
3 years ago
14

If f(x) = 3x - 1 and g(x) = x + 2, find (f+g)(x).

Mathematics
2 answers:
MatroZZZ [7]3 years ago
6 0
<h3>Given:</h3>

f(x) = 3x - 1

g(x) = x + 2

<h3>To Find:</h3>

(f+g)(x) = f(x) + g(x)

<h3>Explanation:</h3>

By putting the values, we get

3x - 1 + x + 2

By simplifying the like terms, we get

3x + x - 1 + 2

= 4x + 1

<h2>Answer:</h2>

(f+g)(x) = 4x + 1

Therefore, <u>A</u><u>.</u><u> </u><u>4</u><u>x</u><u> </u><u>+</u><u> </u><u>1</u> is the correct answer.

kirill115 [55]3 years ago
4 0

Answer:

\boxed {\boxed {\sf A. \ 4x+1}}

Step-by-step explanation:

We are asked to find (f+g)(x). The question is essentially asking us to find the sum of f(x) and g(x).

(f+g)(x)=f(x)+g(x)

We know that f(x) equals 3x-1 and g(x) equals x+2. Substitute the values of the functions in.

(f+g)(x)=(3x-1)+(x+2)

Combine the like terms.

  • 3x and x are like terms (both have the variable "x"
  • -1 and 2 are like terms (both without variables, also known as constants)

(f+g)(x)=(3x+x)+(-1+2)

(f+g)(x)=(4x)+(1)=4x+1

(f+g)(x) is equal to <u>4x+1</u> and the correct answer is A.

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14.5...?

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4 0
3 years ago
The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi
inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.        

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

\displaystyle\frac{dr}{dt} = -7\text{ inch per second}

The volume is decreasing at a constant rate.

\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}

Instant radius = 99 inch

Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

V = \displaystyle\frac{1}{3}\pi r^2 h

Instant volume =

525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}

Differentiating with respect to t,

\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)

Putting all the values, we get,

\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

3 0
3 years ago
When simplified completely, the product of a monomial and a monomial is sometimesalwaysnever a monomial
Vaselesa [24]

Answer:

Always

Step-by-step explanation:

A mononomial's variable can only have exponents 0,1,2,3 etc  so the product will also be a mononomial.

7 0
3 years ago
the seed and skin of a typical avacado is about 30%-40% of the avocados weight. for an 8-ounce avocado, how many ounces of edibl
wolverine [178]

Answer:

Edible fruit amount is 4.8 ounce to 5.6 ounce  

Step-by-step explanation:

Given as

The seed and skin of avocados is about 30%-40%

And the weight of avocados is 8 ounce

So, the weight of seed and skin is about 30% of 8 to 40% of 8

i.e 2.4 ounce to 3.2 ounce

Then the edible fruit is about 60% to 70%

i.e 60% of 8 to 70% of 8

Thus edible fruit of avocados = 4.8 ounce to 5.6 ounce   Answer

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The height of a plant in mm is 7. It doubles each week. Select all expressions that represent the
MaRussiya [10]

Answer:

I only know that it will be 28 mm tall but you have to be more specific

4 0
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