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skad [1K]
2 years ago
5

PLEASEEEEEE HELPPPPPP IM SO CONFUSED IVE BEEN TRYING TO SOLVE FOR DAYS

Mathematics
1 answer:
andre [41]2 years ago
6 0

Answer:

9 days

Step-by-step explanation:

1= 9*(1.04)^d

12.81/9= (1.04)^d

1.423= (1.04)^d

log(1.423)= d *log(1.04)

0.1532=d * 0.017

d= 0.1532/0.017

d=9

The reasonable domain to plot the growth function is in the interval [0,9].

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A sample of 1800 computer chips revealed that 53% of the chips do not fail in the first 1000 hours of their use. The company's p
charle [14.2K]

Answer:

So the value of the test statistic is -0.85.

Step-by-step explanation:

We know that a sample of 1800 computer chips revealed that 53% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature states that 54% of the chips do not fail in the first 1000 hours of their use.

We get that:

n=1800\\\\p_1=53\%=0.53\\\\p_2=54\%=0.54\\

We calculate the standar deviation:

\sigma=\sqrt{\frac{0.53 \cdot (1-0.53)}{n}}=\sqrt{\frac{0.53 \cdot 0.47}{1800}}=0.01176

We calculate the value of the test statistic:

z=\frac{p_1-p_2}{\sigma}=\frac{0.53-0.54}{0.01176}=-0.85

So the value of the test statistic is -0.85.

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3 years ago
What kind of function would be most suitable to model these data
Darya [45]

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Step-by-step explanation:

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3 years ago
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alexandr1967 [171]

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Step-by-step explanation:

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3 years ago
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sergeinik [125]

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so <em>5</em><em> </em><em>p</em><em>o</em><em>u</em><em>n</em><em>d</em><em>s</em><em> </em><em>o</em><em>f</em><em> </em><em> </em><em>p</em><em>e</em><em>p</em><em>p</em><em>e</em><em>r</em><em> </em><em>wou</em><em>ld</em><em> </em><em>c</em><em>o</em><em>s</em><em>t</em><em> </em><em> </em><em> </em><em> </em><em>3</em><em>.</em><em>2</em><em>5</em>

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3 years ago
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