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saw5 [17]
2 years ago
7

Factor. x² – x - 2 How to factor these numbers

Mathematics
1 answer:
zhenek [66]2 years ago
6 0
The factors of this mathematical term is (x-2)(x+1)^2
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Illusion [34]
Absolute value hope this helps
3 0
2 years ago
Please help!! Due tomorrow!!
Marysya12 [62]

The number of doughnuts in bags is 4 times the number of bags of doughnuts. So the number in B bags of doughnuts will be

... 4B

The number of doughnuts in cartons is 10 times the number of cartons of doughnuts, so the number in C cartons will be

... 10C

The total number of doughnuts (T) is the sum of those in bags and those in cartons:

... T = 4B +10C

3 0
3 years ago
You and a friend are heading to Frankie's Fun Park (Columbia, SC). You have $100 for the day, and plan to spend your time riding
Rufina [12.5K]

Answer:

8r + 6s = 100 --- (a)

s = -2 ---- (b)

Step-by-step explanation:

Given

Per ride (r) = $8

Per baseballs (s) = $6

Total = $100

Required

Represent using an equation

If 1 ride is $8.

r rides would be 8r

If 1 baseball is $6

s baseballs would be 6r.

So, total is:

8r + 6s = 100

Solving (b):

Value of s when r = 14

8r + 6s = 100

Substitute 14 for r

8 * 14 + 6s = 100

112+ 6s = 100

Solve for 6s

6s = 100 - 112

6s = -12

Solve for s

s = -12/6

s = -2

4 0
3 years ago
The dimensions of a wooden bench shaped like a rectangular prism are 6' x 3.5' x 2.5'. What is the volume of the bench in cubic
Dafna11 [192]

Answer:

Step-by-step explanation:

Volume of a rectangular prism

V=l*w*h

V=6*3.5*2.5=52.50 ft^3

8 0
3 years ago
Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species
kotegsom [21]

Answer:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

Step-by-step explanation:

The logistic equation is the following one:

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that P(0) = 80, K = 2000.

The number of fish tripled in the first year. This means that P(1) = 3P(0) = 3(80) = 240.

Using the equation for P(1), that is, P(t) when t = 1, we find the value of r.

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

240 = \frac{2000*80e^{r}}{2000 + 80(e^{r} - 1)}

280*(2000 + 80(e^{r} - 1)) = 160000e^{r}

280*(2000 + 80e^{r} - 80) = 160000e^{r}

280*(1920 + 80e^{r}) = 160000e^{r}

537600 + 22400e^{r} = 160000e^{r}

137600e^{r} = 537600

e^{r} = \frac{537600}{137600}

e^{r} = 3.91

Applying ln to both sides.

\ln{e^{r}} = \ln{3.91}

r = 1.36

This means that the expression for the size of the population after t years is:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

4 0
3 years ago
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