According to SSS, RPS and RPQ should be similar angles. Since the length RP is the same, then RQP and RSP should be similar too. Therefore PRS and PRQ should be similar too. Since QP and RS are the same (7) then QR and PS needs to be same in length too.

2x+3 = 4x-7

10 = 2x

x=5

5 0

3 years ago

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Need help please!!!!!!!

stepan [7]

Step-by-step explanation:m okay so the answer is 56 x= 56

6 0

3 years ago

Please find which quadratic equation matches the graph with work attached

lesya [120]

Answer:

Step-by-step explanation:

Firstly, we know that the function must be negative due to its shape. This means that the answer cannot be B

Next we can use the equation $x=\frac{-b}{2a}$ that is used in order to find the vertex of the parabola.

$f(x)=-x^2+6x+7\\a=-1,b=6,c=7\\\\x=\frac{-6}{-2} \\x=3$

As the vertex is at x=3 on the graph, this one could be a contender.

$f(x)=-x^2+6x-7\\a=-1,b=6, c=-7\\\\x=\frac{-6}{-2} \\\\x=3$

This also could be the equation

$f(x)=-x^2-6x-7\\\\a=-1, b=-6, c=-7\\\\x=\frac{6}{-2} \\\\x=-3$

This rules option D out.

For this last step, we can look at where the zeroes would be for each equation. (These values are irrational, so we cannot look at specific number)

$f(x)=-(x^2-6x-7)$

As this equation has a negative value for c, this means that one zero must be positive and the other must be negative.

This means that option A can be ruled out

$f(x)=-(x^2-6x+7)$

As this equation has a positive value for c, this means that both of the zeroes must be positive. This means that it is the only one that fits all of the criteria.

7 0

3 years ago