Answer:
a) 72 °F= 22.22 °C
b) 213.8 °C= 416.84°F
c) 180 °C= 453.15 °K
d) 315 °K= 107.33 °F
e) 1750 °F= 1227.594 °K
f) 0 °K= -459.67 °F
Explanation:
Para realizar el intercambio de unidades debes tener en cuenta las siguientes conversiones:
- Fahrenheit a Celsius:
- Celsius a Fahrenheit: °F= °C*1.8 + 32
- Celsius a Kelvin: °K= °C + 273.15
- Kelvin a Fahrenheit: F= (K -273.15)*1.8 + 32
- Fahrenheit a Kelvin:
Entonces se obtiene:
a) 72 °F= 
=22.22 °C
b) 213.8 °C= 213.8*1.8 + 32= 416.84°F
c) 180 °C= 180°C + 273.15= 453.15 °K
d) 315 °K= (315 -273.15)*1.8 + 32= 107.33 °F
e) 1750 °F= 
= 1227.594 °K
f) 0 °K= (0 -273.15)*1.8 + 32= -459.67 °F
Answer:
1=C
2=B
3=E
4=A
5=D
Explanation:
Closer to 0 is more acidic, closer to 14 is more basic. 7 is neutral and the cut off point between if acidic or basic.
Answer:
7.055 atm
Explanation:
T = (273 + 37)K = <em>310K</em>
The ideal gas constant =<em> 0.0821</em>atm.L/mol.K
Concentration = (0.90g)*(1mol/58.4g/0.100mL) = 0.154mol/L
Molar mass= Concentration*i
Osmotic pressure = Molar mass *the ideal gas constant*T
OP = (0.154)*(1.8)*(0.0821)*(310) = 7.055 atm
SO2<span> molecule </span>have a dipole moment<span> and a </span>CO2<span> molecule doesn't ... </span>Dipole moment<span> of </span>CO2<span> molecule </span>is zero<span>,becoz it is linear molecule,whereas </span>SO2<span> is angular</span>
Answer:
Yes, it is due to the gravitational pull from the moon
Explanation:
The mass of Garfield didn't change during the flight, which is to say, the amount of matter in his body is the same on Earth as on the Moon.
However, <em>weight is a measurement of how strongly mass is pulled towards the ground, due to the gravitational pull.</em>
So even though Garfield's mass is the same, the weight is less due to the lower gravitational pull from the Moon compared to Earth (the weight is one-sixth of the original weight as gravity on the moon is about one-sixth of Earth's). When Garfield returns to Earth, the scale will still read 24 lbs.
