Subtract to find the temperature changes<br><br> for the water and the metal.

Some covalent compounds contain atoms of just one element. true or false?

kifflom [539]

True, because diatomic elements (H2, O2, F2, Br2, I2, N2, Cl2) consist of only one element but are molecules with covalent bonds.

6 0

3 years ago

How many grams of nickel are in a 25.0 g sample of nickel (II) fluoride?

snow_tiger [21]

Answer:

15.17 g

Explanation:

To answer this, we need to find the molar mass of nickel in nickel (II) fluoride. The formula for nickel (II) fluoride is NiF2. This gives us the molar mass of 96.69 g. The mass percentage of nickel is 60.70% approximately (as we divide the molar mass of nickel by that of nickel (II) fluoride), and 60% of 25g gives us 15.17 g

5 0

2 years ago

How many moles of sulfur atoms are in 9.9 moles of Ag2S

GarryVolchara [31]

Answer:

9.9 moles of Ag₂S contain 9.9 moles of sulfur.

Explanation:

Given data:

Number of moles of Ag₂S = 9.9 mol

Number of moles of Sulfur = ?

Solution:

One mole of Ag₂S having 1 mole of sulfur.

In 9.9 moles:

9.9 moles × 1 = 9.9 moles

So 9.9 moles of Ag₂S contain 9.9 moles of sulfur.

6 0

2 years ago

The ksp of zinc carbonate (znco3 is 1.0 × 10–10. what is the solubility concentration of carbonate ions in a saturated solution

Trava [24]

Ksp - solubility product constant is equivalent to equilibrium constant, except this constant is used to determine the solubility of ions of a solid in a solution.
ksp is the product of the soluble ions in the compound. Higher the ksp value, higher the degree of solubility.
ZnCO₃ (s) ---> Zn²⁺ (aq) + CO₃²⁻ (aq)
n n
ksp = [Zn²⁺][CO₃²⁻]
In the equation equal amounts of ions Zn²⁺ and CO₃²⁻ ions are soluble.
amount of ions soluble = n
ksp is therefore equal to;
ksp = n x n
ksp = n²
ksp = 1 * 10⁻¹⁰ M
therefore
1 * 10⁻¹⁰ M = n²
n = 1 x 10⁻⁵ M
therefore concentration of CO₃²⁻ = 1 x 10⁻⁵ M

7 0

3 years ago

Read 2 more answers

The action of some commercial drain cleaners is based on the following reaction: 2 NaOH(s) + 2 Al(s) + 6 H2O(l) → 2 NaAl(OH)4(s)

Blababa [14]

Answer : The volume of $H_2$ gas formed at STP is 7.86 liters.