Hello,
if x≠-3
f(-3)=-2(-3)^3+(-3)²+16(-3)-15=-2*(-27)+9-48-15=54+9-48-15=0
f(x)/g(x)=(-2x^3+x²+16x-15)/(x+3)=(x+3)*(-2x²+7x-5)/(x+3)= -2x²+7x-5
The reflection of any point across the x axis is the symmetric of this point, having x axis as axe of symmetry
Let :
A(1,3) its symmetric vs. x axis is A'(1,-3)
B(-1,5) its symmetric vs. x axis is B'(-1,-5)
C(-3,-3) its symmetric vs. x axis is C'(-3,3)
D(-4,-4) its symmetric vs. x axis is D'(-4,4)
Symmetry vs. the x axis keeps abscises the same & change just the sign of y value
Answer:
yes it is
Step-by-step explanation:
Answer:-4 and 7
Thank you for your service
Answer:
Step-by-step explanation: