I know this is kinda late, but...
You can solve this easily as long as you remember how to find the volume of a cube. v=a^3, when a means length. The length is 1/2 cm, or .5 cm.
So, v+.5^3, which equals .125 cm. Each cube has a that volume. Now, multiply that by how many actual cubes there are, 96.
96 * .125 = 12
Answer:
A die is thrown which means that it can land on either 1-6 on the die.So if you want to find the probability of the multiple of 2 or 3....we have multiplies of 2 in the die from 1-6 which is 2,4 and 6 if you count them they are just 3 numbers and since there is a probability of it to land on any of them it will be 3/6 which is 1/2 if yiu divide by 3 to it's lowest term....Then multiple of 3 is 3,and 6.which will be 2/6 which is 1/3 if u cut to its lowest term. Or in the question means addition sign in probability then it is 2 or 3 which is (1/2)+(1/3)=5/6.Thank you for the question
Personally I'd solve this inequality for y first: y < x-3.
That immediately eliminates (6,2) and (2,6).
Starting from y < x-3 and letting 2 sub for x and -1 sub for y, is the following true or false?
-1 < 2 -3 NO. -1 < -1 is false. Was there a fourth answer choice?
