NaBr < H3O+1 = OH-1 < Na^+1 = Br^-1 < H2O
<span>Least is NaBr (100% dissolved so no NaBr remains, only Na^+1 and Br^-1 </span>
<span>H2O yields 10^-7 M H3O^+1 and 10^-7 M OH^-1 (Kw = 1x10^-14 = [H3O+][OH-] </span>
<span>Na^+1 and Br^-1 will bothe be 0.1 M </span>
<span>H2O is slightly less that 1000 g / L in a 0.1 M NaBr solution, so its concentration is about 55.5 M</span>
Answer:
Equation S= (°C + 117.3)/1.956 °S(25°C) = 72.25°S
Explanation:
To know the difference between the scales, we must initially know the length of our new scale compared to the scale in Celcius degrees, for this we add the absolute value of our melting point and the boiling point | -117.3 ° C | + | 78.3 ° C | = 195.6 ° C
Because our new scale will be divided into 100 equal parts we can know the unit value of each degree ° C concerning degrees ° S. 195.6 / 100 = 1,956 ° C / ° S
For a linear relationship of the scales, the crossing point at ° S = 0.00 is equal to -117.3 ° C. whereby we can clear our equation to know the temperature in degrees Celcius from ° S
°C= -117.3 + °S * 1.956°C/°S
Clearing °S we obtain
°S = (°C + 117.3)/1.956°C/°S
(ii)
In this new scale the temperature of 25°C will be readed as
°S = (25°C+117.3)/1.956°C/°S = 72.25°S
There are 1000 meters in 1 Kilometer.
Hope this helps you. :)