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3 years ago

9q-4= 3r-6 What does r=

Mathematics

2 answers:

Semenov [28]3 years ago

6 0

R= 3q+2/3 i believe.

posledela3 years ago

4 0

R= 2/3 I think!!!!!!!

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Find the distance between the two points in simplest radical form. (-9,5) and (0,0)

7nadin3 [17]

Answer:

$\sqrt{106}$ units

Step-by-step explanation:

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (- 9, 5)

d = $\sqrt{(-9-0)^2+(5-0)^2}$

= $\sqrt{(-9)^2+5^2}$

= $\sqrt{81+25}$

= $\sqrt{106}$

3 0

3 years ago

Use demovires theorem to write the complex number in trigonometric form.

Anastasy [175]

$\sqrt3+i=2\left(\dfrac{\sqrt3}2+\dfrac12i\right)$

$\begin{cases}\cos\dfrac\pi6=\dfrac{\sqrt3}2\\\\\sin\dfrac\pi6=\dfrac12\end{cases}$

$\implies\sqrt3+i=2e^{i\pi/6}$

By DeMoivre's theorem,

$(\sqrt3+i)^3=(2e^{i\pi/6})^3=8e^{i\pi/2}=8\left(\cos\dfrac\pi2+i\sin\dfrac\pi2\right)=8i$

3 0

3 years ago

-3x-3y=3 ,y=-5x-17 solving systems by substitution

Law Incorporation [45]

Answer:

(-4, 3)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Solving systems of equations by substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

-3x - 3y = 3

y = -5x - 17

Step 2: Solve for x

Substitution

Substitute in y: -3x - 3(-5x - 17) = 3
Distribute -3: -3x + 15x + 51 = 3
Combine like terms: 12x + 51 = 3
Isolate x term: 12x = -48
Isolate x: x = -4

Step 3: Solve for y

Define equation: y = -5x - 17
Substitute in x: y = -5(-4) - 17
Multiply: y = 20 - 17
Subtract: y = 3

8 0

3 years ago

PLEASE HELP MEEE ❗‼️‼️❗‼️ Find RS A) 38 B) 35 C) 37 D) 40

Marat540 [252]

The interior angles sum to 180°, so the missing angle has measure

180° - 106° - 12° = 62°

Use the law of sines to find RS:

sin(106°)/RS = sin(62°)/34 ⇒ RS = 34 sin(106°)/sin(62°) ≈ 37

4 0

2 years ago

3 balls are placed in 3 boxes at random. What is the probability that exactly 2 boxes remain empty

matrenka [14]

If 2 boxes remain empty, it means that we put all three balls in one single box.

Suppose the full box is box number 1. For each ball, we have three choices - we may put it in box number 1, 2 or 3. This means that each box has a 1/3 chance of receiving each ball.

So:

we choose box 1 for ball 1 - that's a 1/3 chance
we choose box 1 for ball 2 - that's a 1/3 chance
we choose box 1 for ball 3 - that's a 1/3 chance

So, the probability of putting all balls in box 1 is

$\dfrac{1}{3}\times\dfrac{1}{3}\times\dfrac{1}{3} = \dfrac{1}{3^3}$

But this is the probability of putting all ballx in box 1, and you can repeat this logic for box 2 and 3.

So, the probability of putting all balls in one single box is 1/27 for each box, for a total of

$\dfrac{1}{27} \times 3 = \dfrac{1}{9}$

5 0

3 years ago