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Novay_Z [31]
2 years ago
5

-a to the third power - b to the second power if a= -3 and b= -4

Mathematics
1 answer:
scoray [572]2 years ago
3 0

Answer:

-a to the third power is 27

-b to the second power is 16.

Step-by-step explanation:

-1 times (-3) is 3. And 3 to the 3rd power is 27.

-1 times (-4) is 4. And 4 to the 2nd power is 16.

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Answer: 207/4 or -51.75

Step-by-step explanation:

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3 years ago
The weight of mr nazeer is 7 times that of his son. What's the ratio of their weights?
Mekhanik [1.2K]

Answer:

<h3>7:1</h3>

Step-by-step explanation:

Let the weight of mr nazeer be x

Let the weight of his son be y

If the weight of mr nazeer is 7 times that of his son, then x = 7y

To get the ratio of their weight:

Ratio = weight of father/weight of son

Ratio = 7y/y

Ratio = 7/1

Ratio = 7:1

Hence the ratio of their weights is 7:1

3 0
3 years ago
A certain line has a slope of 3/2. Select all pairs of points that may be on the line.
Marta_Voda [28]
C is the correct answer
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Gabrielle is 9 years younger than Mikhail. The sum of their ages is 35. What is Mikhail's age?
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35 - 9 = 26 so mikhail is 26
8 0
3 years ago
Read 2 more answers
Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.
Leviafan [203]

Answer:

Option D. 3.73​

Step-by-step explanation:

we know that

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

and

sin^{2}(\alpha)+cos^{2}(\alpha)=1

step 1

Find cos(X)

we have

sin(x)=\frac{1}{2}

we know that

sin^{2}(x)+cos^{2}(x)=1

substitute

(\frac{1}{2})^{2}+cos^{2}(x)=1

cos^{2}(x)=1-\frac{1}{4}

cos^{2}(x)=\frac{3}{4}

cos(x)=\frac{\sqrt{3}}{2}

step 2

Find tan(x)

tan(x)=sin(x)/cos(x)

substitute

tan(x)=1/\sqrt{3}

step 3

Find sin(y)

we have

cos(y)=\frac{\sqrt{2}}{2}

we know that

sin^{2}(y)+cos^{2}(y)=1

substitute

sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1

sin^{2}(y)=1-\frac{2}{4}

sin^{2}(y)=\frac{2}{4}

sin(y)=\frac{\sqrt{2}}{2}

step 4

Find tan(y)

tan(y)=sin(y)/cos(y)

substitute

tan(y)=1

step 5      

Find tan(x+y)

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

substitute

tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73

7 0
3 years ago
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