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2 years ago

5

-a to the third power - b to the second power if a= -3 and b= -4

1 answer:

scoray [572]2 years ago

3 0

Answer:

-a to the third power is 27

-b to the second power is 16.

Step-by-step explanation:

-1 times (-3) is 3. And 3 to the 3rd power is 27.

-1 times (-4) is 4. And 4 to the 2nd power is 16.

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18/4(-11.5)<br><br> Answer that question <br> Thank You!!!

Paha777 [63]

Answer: 207/4 or -51.75

Step-by-step explanation:

3 0

3 years ago

The weight of mr nazeer is 7 times that of his son. What's the ratio of their weights?

Mekhanik [1.2K]

Answer:

<h3>7:1</h3>

Step-by-step explanation:

Let the weight of mr nazeer be x

Let the weight of his son be y

If the weight of mr nazeer is 7 times that of his son, then x = 7y

To get the ratio of their weight:

Ratio = weight of father/weight of son

Ratio = 7y/y

Ratio = 7/1

Ratio = 7:1

Hence the ratio of their weights is 7:1

3 0

3 years ago

A certain line has a slope of 3/2. Select all pairs of points that may be on the line.

Marta_Voda [28]

C is the correct answer

4 0

3 years ago

Gabrielle is 9 years younger than Mikhail. The sum of their ages is 35. What is Mikhail's age?

Svetllana [295]

35 - 9 = 26 so mikhail is 26

8 0

3 years ago

Read 2 more answers

Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.

Leviafan [203]

Answer:

Option D. 3.73

Step-by-step explanation:

we know that

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

and

$sin^{2}(\alpha)+cos^{2}(\alpha)=1$

step 1

Find cos(X)

we have

$sin(x)=\frac{1}{2}$

we know that

$sin^{2}(x)+cos^{2}(x)=1$

substitute

$(\frac{1}{2})^{2}+cos^{2}(x)=1$

$cos^{2}(x)=1-\frac{1}{4}$

$cos^{2}(x)=\frac{3}{4}$

$cos(x)=\frac{\sqrt{3}}{2}$

step 2

Find tan(x)

$tan(x)=sin(x)/cos(x)$

substitute

$tan(x)=1/\sqrt{3}$

step 3

Find sin(y)

we have

$cos(y)=\frac{\sqrt{2}}{2}$

we know that

$sin^{2}(y)+cos^{2}(y)=1$

substitute

$sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1$

$sin^{2}(y)=1-\frac{2}{4}$

$sin^{2}(y)=\frac{2}{4}$

$sin(y)=\frac{\sqrt{2}}{2}$

step 4

Find tan(y)

$tan(y)=sin(y)/cos(y)$

substitute

$tan(y)=1$

step 5

Find tan(x+y)

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

substitute

$tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73$

7 0

3 years ago