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Sidana [21]
3 years ago
14

What term is used for the electrons in the outermost shell or energy level

Chemistry
2 answers:
asambeis [7]3 years ago
6 0

Answer:

Valence Electrons

Explanation:

stiv31 [10]3 years ago
6 0

Answer:

Valence

Explanation:

The outermost shell are the valence electrons

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A balloon is filled with 12 L of air at a pressure of 2 atm. What is the volume of the balloon if the pressure is changed to 3 a
mihalych1998 [28]

Answer:

8L

Explanation:

Using Boyle's law which states that the volume of a given mass of gas is inversely proportional to the pressure, provided temperature remains constant

P1V1= P2V2

P1 =  2atm, V1 = 12L ,

P2 = 3atm , V2 =

12 × 2 = V2 × 3

Divide both sides by 3

V2 = 24 ÷ 3

V2 = 8L

I hope this was helpful, please mark as brainliest

3 0
3 years ago
Which element in period 2 of the periodic table is the most reactive nonmetal?
ziro4ka [17]
<span>d. flourine </span> fluorine<span> is the most reactive halogen

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5 0
3 years ago
What must be true for a substance to be able to dissolve in water?
JulsSmile [24]
B. i think not 100% sure 
6 0
3 years ago
Pure nitrogen (N2) and pure hydrogen (H2) are fed to a mixer. The product stream has 40.0% mole nitrogen and the balance hydroge
LuckyWell [14K]

Explanation:

The given data is as follows.

        Mass flow rate of mixture = 1368 kg/hr

      N_{2} in feed = 40 mole%

This means that H_{2} in feed = (100 - 40)% = 60%

We assume that there are 100 total moles/hr of gas (N_{2} + H_{2}) in feed stream.

Hence, calculate the total mass flow rate as follows.

           40 moles/hr of N_{2}/hr (28 g/mol of N_{2}) + 60 moles/hr of H_{2}/hr (2 g/mol of H_{2})

                  40 \times 28 g/hr + 60 \times 2 g/hr    

                  = 1120 g/hr + 120 g/hr

                  = 1240 g/hr

                  = \frac{1240}{1000}              (as 1 kg = 1000 g)

                  = 1.240 kg/hr

Now, we will calculate mol/hr in the actual feed stream as follows.

                 \frac{100 mol/hr}{1.240 kg/hr} \times 1368 kg/hr

                   = 110322.58 moles/hr

It is given that amount of nitrogen present in the feed stream is 40%. Hence, calculate the flow of N_{2} into the reactor as follows.

                       0.4 \times 110322.58 moles/hr

                      = 44129.03 mol/hr

As 1 mole of nitrogen has 28 g/mol of mass or 0.028 kg.

Therefore, calculate the rate flow of N_{2} into the reactor as follows.

                       0.028 kg \times 44129.03 mol/hr

                         = 1235.612 kg/hr

Thus, we can conclude that the the feed rate of pure nitrogen to the mixer is 1235.612 kg/hr.

3 0
3 years ago
What is an example of a Low Energy-created depositional environment?
sweet-ann [11.9K]

Answer:

River flood plains, swamps, lakes, lagoons, marshes, and offshore.

Explanation:

Slow-moving currents prevent coarse-grained sediment from migrating into low-energy depositional environments. Fine materials can be carried long distances before they can settle out in the absence of waves and currents.

4 0
3 years ago
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