The direction of heat flow is increased which means blocks temperature is higher and hotter than it was before
Explanation:
When solid cadmium sulfide reacts with an aqueous solution of sulfuric acid then the reaction will be as follows.
![CdS(s) + H_{2}SO_{4}(aq) \rightarrow CdSO_{4}(aq) + H_{2}S(g)](https://tex.z-dn.net/?f=CdS%28s%29%20%2B%20H_%7B2%7DSO_%7B4%7D%28aq%29%20%5Crightarrow%20CdSO_%7B4%7D%28aq%29%20%2B%20H_%7B2%7DS%28g%29)
Hence, ionic equation for this reaction is as follows.
![CdS(s) + 2H^{+}(aq) + SO^{2-}_{4}(aq) \rightarrow Cd^{2+}(aq) + SO^{2-}_{4}(aq) + H_{2}S(g)](https://tex.z-dn.net/?f=CdS%28s%29%20%2B%202H%5E%7B%2B%7D%28aq%29%20%2B%20SO%5E%7B2-%7D_%7B4%7D%28aq%29%20%5Crightarrow%20Cd%5E%7B2%2B%7D%28aq%29%20%2B%20SO%5E%7B2-%7D_%7B4%7D%28aq%29%20%2B%20H_%7B2%7DS%28g%29)
Therefore, net ionic equation for this reaction is as follows.
![CdS(s) + 2H^{+}(aq) \rightarrow Cd^{2+}(aq) + H_{2}S(g)](https://tex.z-dn.net/?f=CdS%28s%29%20%2B%202H%5E%7B%2B%7D%28aq%29%20%5Crightarrow%20Cd%5E%7B2%2B%7D%28aq%29%20%2B%20H_%7B2%7DS%28g%29)
Sorry the answer might be a little late but it would be <span>Simple squamous</span>