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Airida [17]
3 years ago
12

What is milliliter the same as?

Chemistry
2 answers:
Klio2033 [76]3 years ago
8 0

Answer:

1 cubic centimeter

Explanation:

lubasha [3.4K]3 years ago
3 0

Answer:

milliliter is the same as cm^3

Explanation:

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A solution is prepared by dissolving 4.40 g of KSCN in enough water to make 200 mL of solution. What is the concentration of the
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First find the number of moles of KSCN is in 4.40g of KSCN 1. Number of moles = mass given (4.40g) / molecular weight(MW) (KSCN) - to calculate MW, look for each element in the periodic table and add their atomic weight 2. Convert 200mL to liters 3. Concentration = number of moles/ volume in liters from (#2)
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4 0
2 years ago
Wastewater from a cement factory contains 0.280 g of Ca2+ ion and 0.0220 g of Mg2+ ion per 100.0 L of solution. The solution den
faltersainse [42]

<u>Answer:</u> The concentration of Ca^{2+}\text{ and }Mg^{2+} ions are 2.797 ppm and 0.212 ppm respectively.

<u>Explanation:</u>

To calculate the mass of solution, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Volume of gold = 100 L = 100000 mL    (Conversion factor:  1 L = 1000 mL)

Density of gold = 1.001 g/mL

Putting values in above equation, we get:

1.001g/mL=\frac{\text{Mass of solution}}{100000mL}\\\\\text{Mass of solution}=1.001\times 10^5g

To calculate the concentration in ppm (by mass), we use the equation:

ppm=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6

  • <u>Calculating the concentration of calcium ions:</u>

Mass of Ca^{2+ ions = 0.280 g

Putting values in above equation, we get:

ppm(Ca^{2+})=\frac{0.280g}{1.001\times 10^5}\times 10^6=2.797ppm

  • <u>Calculating the concentration of magnesium ions:</u>

Mass of Mg^{2+ ions = 0.0220 g

Putting values in above equation, we get:

ppm(Mg^{2+})=\frac{0.0220g}{1.001\times 10^5}\times 10^6=0.212ppm

Hence, the concentration of Ca^{2+}\text{ and }Mg^{2+} ions are 2.797 ppm and 0.212 ppm respectively.

7 0
3 years ago
If 30g of HCl is reacted with excess NaOH, and 10g of NaCl is produced, what is the theoretical yield of the experiment?
KATRIN_1 [288]
1. %yield = actual yield / theoretical yield x 100
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Hope This Helps! :3
4 0
3 years ago
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