Answer:
Knowing the mass of chlorine in each mixture will enable you find the empirical formulas that will lead to molecular formulas for the compounds in the mixture.This information will help you determine which mixture has a higher proportion of the compound in question.
Explanation:
In determining the percent composition of a compound in a mixture,mass of a compound will be the first step to be determined.This will then allow you to find mole to mole ratio of all elements in that compound.Having mole ratio information, and mass, it will be possible to find ratio of ions in the compound,and determine the mixture with higher proportion of the compound.
Molecular weight and the empirical formula of the compound will led you to the molecular formula of the compound,that will show you the mole ratios which now you can use to determine proportions of the compound in a mixture.
Answer:
the new pressure is 2.09 atm
Explanation:
you have to use gay lussac's law so the formula is
p1/t1 = p2/t2
and convert C to Kelvin k=C+273.15
1.72atm/294.15 = p2/358.15
solve for p2 by multiplying 358.15 on both sides
p2=2.09 atm
Answer:
0.3477 grams
The conversion factor is 1/1000
Explanation:
347.7 mg = 0.3477 grams
1 mg = 1x10⁻³ g
1 g / 1000 mg . 347.7 mg = 0.3477 grams
Answer:
Explanation:
Formal charge of ICl₂⁻
Formal charge = group no - ( no of non bonding electrons +no of bonds)
In I there are 7 electrons in outermost orbit . If we add one more electrons due to - ve charge on the ion , it becomes eight . This centrally placed iodine forms two single bond with two chlorine atoms on either side.
Each of chlorine atoms also contains 7 valance electrons like iodine.
So formal charge of chlorine
= group no - ( no of non bonding electrons +no of bonds)
= 7 - ( 6 + 1 )
= 0
So formal charge of iodine
= group no - ( no of non bonding electrons +no of bonds)
= 7 - ( 5 + 2 )
=0
Formal charge of ICl₂⁺
In this case , central iodine will have only 6 valence electrons due to absence one electron.
So formal charge of chlorine in ICl₂⁺
= group no - ( no of non bonding electrons +no of bonds)
= 7 - ( 6 + 1 )
= 0
formal charge of iodine in in ICl₂⁺
7 - ( 4 + 2)
= 1
Answer:
ok but this number is for school another one number soon tell you
