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sashaice [31]
3 years ago
7

What is the sum of the first 20 terms of the arithmetic sequence shown? \displaystyle \frac{1}{3} 3 1 ​ , \displaystyle \frac{2}

{3} 3 2 ​ , 1, \displaystyle \frac{4}{3} 3 4 ​ , \displaystyle \frac{5}{3} 3 5 ​ , ...
Mathematics
1 answer:
Murrr4er [49]3 years ago
5 0

Answer:

70

Step-by-step explanation:

a_1 = First term = \dfrac{1}{3}

d = Common difference = \dfrac{2}{3}-\dfrac{1}{3}=\dfrac{1}{3}

n = Number of terms = 20

Sum of arithmetic progression is given by

S=\dfrac{n}{2}[2a_1+(n-1)d]\\\Rightarrow S=\dfrac{20}{2}\times (2\times \dfrac{1}{3}+(20-1)\dfrac{1}{3})\\\Rightarrow S=70

The sum of the first 20 terms of the arithmetic sequence is 70.

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We are given that county courthouse is shaped like a trapezoid.

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