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3 years ago

What is the product of twenty hundredths and sixty-five thousandths

Mathematics

1 answer:

ryzh [129]3 years ago

7 0

Answer:

0.013

Step-by-step explanation:

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Brianna and let kelci are raising money for a class field trip. Brianna has raised 3 times more money than kelci, but together t

ddd [48]

Let $x be the amount of money which Kelci has raised. Brianna has raised 3 times more money than kelci, then she has raised $3x. Totally both have aised $(x+3x)=$4x.

Since together they have raised more than $300, then 4x>300,

$x\ \textgreater \ \dfrac{300}{4}$ .
Answer: the inequality $x\ \textgreater \ \dfrac{300}{4}$ can be used to determine the amount of money kelci has raised

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3 years ago

Anne is checking out of a hotel. The price

kolezko [41]

The tax is 2.88 so it would be 48.00 +2.88=50.88
She will pay $50.88 with tax

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2 years ago

What is 10 times as many as

Talja [164]

Answer:

To answer this question, more information needs to be disclosed.

3 0

2 years ago

Solve the inequality 4b−4≤−20

devlian [24]

Answer:

b ≤ -4

Step-by-step explanation:

4b−4≤−20

4b - 4 + 4 ≤ - 20 + 4

4b ≤ -16

Divide both sides by 4

b ≤ -4

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2 years ago

Evaluate the integral Integral ∫ from (1,2,3 ) to (5, 7,-2 ) y dx + x dy + 4 dz by finding parametric equations for the line seg

n200080 [17]

$\vec F(x,y,z)=y\,\vec\imath+x\,\vec\jmath+3\,\vec k$

is conservative if there is a scalar function $f(x,y,z)$ such that $\nabla f=\vec F$ . This would require

$\dfrac{\partial f}{\partial x}=y$

$\dfrac{\partial f}{\partial y}=x$

$\dfrac{\partial f}{\partial z}=3$

(or perhaps the last partial derivative should be 4 to match up with the integral?)

From these equations we find

$f(x,y,z)=xy+g(y,z)$

$\dfrac{\partial f}{\partial y}=x=x+\dfrac{\partial g}{\partial y}\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)$

$f(x,y,z)=xy+h(z)$

$\dfrac{\partial f}{\partial z}=3=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=3z+C$

$f(x,y,z)=xy+3z+C$

so $\vec F$ is indeed conservative, and the gradient theorem (a.k.a. fundamental theorem of calculus for line integrals) applies. The value of the line integral depends only the endpoints:

$\displaystyle\int_{(1,2,3)}^{(5,7,-2)}y\,\mathrm dx+x\,\mathrm dy+3\,\mathrm dz=\int_{(1,2,3)}^{(5,7,-2)}\nabla f(x,y,z)\cdot\mathrm d\vec r$

$=f(5,7,-2)-f(1,2,3)=\boxed{18}$

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3 years ago