Simplify 79.5-2.58 x (3.63-1.63) to the third power

4193 times 381 (with work)

zaharov [31]

4193

0381=

00,004,193

00,335,440

01,257,900=

1,597,533

3 0

2 years ago

Read 2 more answers

Which graph matches the following description?

skad [1K]

Answer:

The third image is the correct answer.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

During strenuous exercise, an athlete can burn 12 calories per minute on a treadmill and 8.5 calories per minute on an elliptica

Irina18 [472]

Hope it helps 10 mins on the elliptical and 12 on the treadmil

3 0

2 years ago

For the function f(x)

WITCHER [35]

Given:

The function is

$f(x)=\dfrac{8\sqrt[3]{x}-8}{9}$

To find:

The inverse function $f^{-1}(x)$ .

Solution:

We have,

$f(x)=\dfrac{8\sqrt[3]{x}-8}{9}$

Step 1: Putting f(x)=y, we get

$y=\dfrac{8\sqrt[3]{x}-8}{9}$

Step 2: Interchange x and y.

$x=\dfrac{8\sqrt[3]{y}-8}{9}$

Step 3: Isolate variable y.

$9x=8\sqrt[3]{y}-8$

$9x+8=8\sqrt[3]{y}$

$\dfrac{9x+8}{8}=\sqrt[3]{y}$

Taking cube on both sides, we get

$\left(\dfrac{9x+8}{8}\right)^3=y$

$y=\left(\dfrac{9x+8}{8}\right)^3$

Step 4: Putting $y=f^{-1}(x)$ , we get

$f^{-1}(x)=\left(\dfrac{9x+8}{8}\right)^3$

Therefore, the correct option is C.

4 0

2 years ago

Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=9\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

so

$A=(12)(7)-(8)(3)$

$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

so

$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

so

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

so

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

7 0

3 years ago