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Paraphin [41]
3 years ago
10

In order to make 159 ml of a 0.135 M benzoic acid solution, what mass of benzoic acid (C7H6O2) is required?

Chemistry
1 answer:
STALIN [3.7K]3 years ago
8 0

Answer:

Explanation:

159 mL of .135 M benzoic acid will contain

.159 x .135 = .021465 moles of benzoic acid.

Molecular weight of benzoic acid = 122 gm

grams of .021465 moles = 122 x .021465 = 2.6 grams .

So 2.6 grams of benzoic acid will be required .

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