Answer:
Postulate: Gas particles are extremely small and are far apart.
The activities can be used to demonstrate the postulate is :
<u>Observing colored gas spreading into an inverted jar placed on top of a jar containing the gas</u>
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Explanation:
colored gas spreading into an inverted jar placed on top of a jar containing the gas:
This occur because of two reasons:
1. <em><u>The Gaseous particles are largely spaced . There is large distance between the gases molecule</u></em>
<em><u>2. The gases are in continuous motion . Hence they posses very high kinetic energy . This is the reason they mixes quickly if placed in a jar.</u></em>
<em><u>This occur by the process of diffusion. </u></em>
Diffusion of Gases: The intermixing of particles from the region of high concentration to low concentration.
The coloured gas goes into the space between the gaseous molecule present in the jar.(Gases are far apart)
As soon as the coloured gas is mixed in the jar , It spread quickly by diffusion because , The gaseous particles are extremely small and are far apart.
Answer:
6.82 kg
Explanation:
Given that the amount of water is 15L and we know that the density of water is ≈ 1kg/L. The mass of water is given by mass = volume x density, i.e,
mass = 15 x 1 = 15 kg. Also the specific heat capacity of water is 4.186 KJ/kg.
The sublimation enthalpy of dry ice is 571 KJ/kg.
Now, the amount of heat lost by water is entirely used up for the sublimation (conversion from soild to gas) of dry ice. And the heat (Q) lost by water is given as : Q = mCΔT, where m is the mass of water, C the specific heat capacity of water and ΔT the change in temperature.
Here, Q = 15 x 4.186 x (90 - 28) = 3892.98 KJ.
This amount of heat is taken up by the dry ice for its sublimation. Also the energy taken by dry ice (Q') for its sublimation is given by: Q' = m'L', where m' is the mass of dry ice, L' is the latent heat of sublimation (i.e, the amount of heat required per kg of a substance to sublime) of dry ice amd L' = 571 KJ/kg.
Now, Q' =m'L' = heat lost by water = 3892.98KJ.
And, m'L' = m' x 571 KJ/kg = 3892.98 KJ. (Dividing with 571)
Therefore, m' = 6.82 kg.
Toothpaste is an abrasive that contains many things, but mainly phosphates.
I’m soooo confusing with what your question is lol
A gas bottle contains 8. 61×1023 oxygen molecules at a temperature of 359. 0 k then the thermal energy of the gas is 6.35KJ.
<h3>What is thermal energy? </h3>
Thermal energy is the energy contained within a system which is responsible for its temperature. Heat is also termed as flow of thermal energy.
Thermal energy is directly proportional to the temperature. As temperature increase thermal energy increases.
Given,
temperature = 395K
Number of oxygen molecules= 8.61 × 10^(23)
Firstly we will calculate the number of moles = N/A
where A is the avagadro number = 6.022 × 10^(23)
number of moles = 8.61 × 10^(23)/6.022 ×10^(23)
number of moles = 1.42moles
Using the energy equation,
E = 3/2 × nRT
where R is the gas constant = 8.314J/molK
E = 3/2 × 1.42 × 8.314 × 359
= 6357.4J
= 6.35KJ
Thus, we found that the thermal energy of the gas is 6.35KJ.
learn more about thermal energy:
brainly.com/question/2409175
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