For a balance chemical equation:
The number of atoms of a molecule should remain conserved that is total number of atom of a molecule in reactant side should equal to the number of atoms of a molecule in the product side.
Here also the number of atoms of an element should remain conserved on both sides, So the answer is option B.
That is
B) 3CuCl₂ + 2Al ---> 2AlCl₃ + 3Cu
Here the number of atoms of Cu, Cl and Al are equal in both side , reactant as well as product.
Answer:
Hope this helps!
Explanation:
Ans: 15.1 grams
Given reaction:
Na2CO3 + Ca(OH)2 → 2NaOH + CaCO3
Mass of Na2CO3 = 20.0 g
Molar mass of Na2CO3 = 105.985 g/mol
# moles of Na2CO3 = 20/105.985 = 0.1887 moles
Based on the reaction stoichiometry: 1 mole of Na2CO3 produces 2 moles of NaOH
# moles of NaOH produced = 0.1887*2 = 0.3774 moles
Molar mass of NaOH = 22.989 + 15.999 + 1.008 = 39.996 g/mol
Mass of NaOH produced = 0.3774*39.996 = 15.09 grams
Answer:
0.2M NaOh
Explanation:
there are 0.2 mol of NaOH in 8.0 g. (8.0/40) =0.2. Molarity = mol/L = 0.2M.
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Blueing. ...
Powder Coating.

Here we go ~
Energy difference btween the two electronic states can be expressed as :

[ h = planks constant,
= frequency ]



