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marishachu [46]
3 years ago
5

Can the probability of an event be 1.5? Explain. i need help

Mathematics
2 answers:
bixtya [17]3 years ago
7 0

Answer:

No

Step-by-step explanation:

Tresset [83]3 years ago
6 0
<h3>No it is never possible</h3>

Why not? Because the probability is always between 0 and 1, inclusive of both endpoints.

0 represents impossibility

1 represents absolute certainty

The value 1.5 is larger than 1, so it is outside the range of 0 to 1.

Saying a probability of 1.5 is like saying "the chances of an event happening are 150%" but the largest the percentage can go is 100%, which represents absolute certainty.

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12x^3-11x^2+9x+18 divided by 4x+3
atroni [7]
12x^3-11x^2+9x+18 divided by 4x+3

put he division into fraction

12x^3-11x^2+9x+18/4 x +3

reduced fraction by 2

12x^3-11x^2+9x+9/2 x +3

calculate sum

12x^3-11x^2+27/2 x +3
that is your answer ^

hope this helps :)
3 0
2 years ago
If ƒ(x) = 2x2 + 3, then which of the following represent ƒ(x + 1)?
romanna [79]
Sub (x+1) for x

f(x+1)=2(x+1)^2+3
f(x+1)=2(x^2+2x+1)+3
f(x+1)=2x^2+4x+2+3
f(x+1)=2x^2+4x+5

D is answer
3 0
3 years ago
Read 2 more answers
Find the median.<br> 2, 20, 19, 15, 11,9,7,1<br> OA. 10<br> OB.<br> 10.5<br> c. 19<br> D. 20
pickupchik [31]

Answer:

A. 10

Step-by-step explanation:

First put the numbers in order from least to greatest then find the two numbers in the center of that since there is an even number of numbers there will be two the add and divide by two and you get 10.

1,2,7,9,11,15,19,20

9+11=20

20/2=10

3 0
3 years ago
Read 2 more answers
5/8 divided by 6 5/6 in fractional form. ➗✏️❓⁉️
ser-zykov [4K]

Answer:

15/164

Step-by-step explanation:

5/8 ÷ 6 5/6 = 15 / 164

3 0
3 years ago
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When you are trying to find the endpoint when given the midpoint and one point, what would the new formula be? Manipulate the fo
MariettaO [177]

Answer:

(x_2,y_2) = (2x_m - x_1 ,2y_m - y_1 )

Step-by-step explanation:

Given

\left(\frac{x_1+\:x_2}{2},\:\:\frac{y_{1\:}+y_2}{2}\right)\:=\:\left(x_m,\:y_m\right)

Required

Determine x2, y2

Start by splitting the expression

x_m = \left(\frac{x_1+\:x_2}{2}) and y_m = (\frac{y_{1\:}+y_2}{2})

Solving for x2 in x_m = \left(\frac{x_1+\:x_2}{2})

Multiply through by 2

2 * x_m = \frac{x_1 + x_2}{2} * 2

2x_m = x_1 + x_2

Make x2 the subject;

x_2 = 2x_m - x_1

Similarly:

y_m = (\frac{y_{1\:}+y_2}{2})

Multiply through by 2

2 * y_m = \frac{y_1 + y_2}{2} * 2

2y_m = y_1 + y_2

Make y2 the subject;

y_2 = 2y_m - y_1

Hence:

(x_2,y_2) = (2x_m - x_1 ,2y_m - y_1 )

7 0
3 years ago
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