Can the probability of an event be 1.5? Explain. i need help

Mathematics

2 answers:

bixtya [17]3 years ago

7 0

Answer:

Step-by-step explanation:

Tresset [83]3 years ago

6 0

<h3>No it is never possible</h3>

Why not? Because the probability is always between 0 and 1, inclusive of both endpoints.

0 represents impossibility

1 represents absolute certainty

The value 1.5 is larger than 1, so it is outside the range of 0 to 1.

Saying a probability of 1.5 is like saying "the chances of an event happening are 150%" but the largest the percentage can go is 100%, which represents absolute certainty.

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The function f(x)=-10(x)(x-4) represents the approximate height of a projectile launch on the ground into the air as a function

ELEN [110]

Answer:

4 seconds.

Step-by-step explanation:

The function f(x)=-10(x)(x-4) ........ (1), represents the approximate height of a projectile launch on the ground into the air as a function of time in seconds x.

Now, we are asked that for how long from the launch does the projectile stays in the air.

Therefore, we have to solve the equation (1) making f(x) as zero.

Hence, 10x(x - 4) = 0

⇒ x = 0 or x = 4

(As x can not be zero since at x = 0 sec, the projectile was at the ground.}

Hence, x = 4 seconds.

Therefore, the projectile was in the air for 4 seconds. (Answer)

4 0

3 years ago

Read 2 more answers

A ball is thrown into the air with a velocity of 34 ft/s. It's height in feet after t seconds is given by y=34t-26(t)^2. Find th

kkurt [141]

Answer:

The average velocity of the ball at the given time interval is -122.3 ft/s

Step-by-step explanation:

Given;

velocity of the ball, v = 34 ft/s

height of the ball, y = 34t - 26t²

initial time, t₀ = 3 seconds

final time, t = 3 + 0.01 = 3.01 seconds

At t = 3 s

y(3) = 34(3) - 26(3)² = -132

The average velocity of the ball in ft/s is given as;

$V_{avg} = \frac{y(3.01)-y(3)}{3.01 -3}\\\\V_{avg} = \frac{34(3.01)-26(3.01)^2-y(3)}{3.01 -3}\\\\V_{avg} = \frac{-133.223-y(3)}{0.01}\\\\V_{avg} = \frac{-133.223-(-132)}{0.01}\\\\V_{avg} =\frac{-1.223}{0.01}\\\\V_{avg} = -122.3 \ ft/s$