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TiliK225 [7]
3 years ago
7

Which is NOT considered as a property of electromagnetic waves: 5

Physics
1 answer:
OlgaM077 [116]3 years ago
4 0

Answer:

require a medium to propagate

Explanation:

this is because electromagnetic waves can travel through vacuum at the speed of 3.0 x 10^8 m/s

because they don't need particles to transfer energy

hope this helps

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1. How much heat energy is required to raise the temperature of a 5 kg aluminium bar
Ray Of Light [21]

Answer:

180 kJ

Explanation:

Given that:

Mass (m) = 5 kg

Initial temperature (T1) = 28°C

Final temperature (T2) = 68°C

The change in temperature (ΔT) = T2 - T1 = 68°C - 28°C = 40°C

Specific heat capacity of aluminium (c) = 900 J/kg°C

The quantity of heat energy required (q) is given by:

q = mcΔT

q = 5 kg × 900 J/kg°C × 40°C

q =  180000 Joules

q = 180 kJ

Therefore 180 kJ is required to raise the temperature of aluminium from 28°C to 68°C.

5 0
3 years ago
What are the types of nuclear radiation ? (Particles let off by nuclear<br> materials.) *
Neko [114]

Answer:

Because nuclear decay releases ionizing radiation (alpha, beta, and gamma radiation) we call such compounds radioactive.

Explanation:

6 0
3 years ago
A 100kg cannon at rest contains a 10kgcannonball. when fired,
slega [8]

Answer:

9 m/s

Explanation:

mass of cannon, M = 100 kg

mass of cannon ball, m = 10 kg

velocity of cannon ball, v = 90 m/s

Let the recoil velocity of cannon is V.

Us ethe conservation of linear momentum, as no external force is acting on the system, so the linear momentum of the system is conserved.

Momentum before the firing = momentum after the firing

M x 0 + m x 0 = M x V + m x v

0 = 100 x V + 10 x 90

V = - 9 m/s

Thus, the recoil velocity of cannon is 9 m/s.

4 0
3 years ago
The center of a moon of mass m is a distance D from the center of a planet of mass M. At some distance x from the center of the
nataly862011 [7]

Answer with Explanation:

Let  rest mass m_0 at point P  at  distance x from center of the planet, along a line connecting the centers of planet and the moon.

Mass of moon=m

Distance between the center of moon and center of planet=D

Mass of planet=M

We are given that net force on an object will be zero

a.We have to derive an expression for x in terms of m, M and D.

We know that gravitational force=\frac{GmM}{r^2}

Distance of P from moon=D-x

F_m=Force applied on rest mass due to m

F_m=Force on rest mass due to mas M

F_M=F_m because net force is equal to 0.

F_m=F_M

\frac{Gm_0m}{(D-x)^2}=\frac{Gm_0M}{x^2}

\frac{m}{(D-x)^2}=\frac{M}{x^2}

\frac{x^2}{(D-x)^2}=\frac{M}{m}

\frac{x}{D-x}=\sqrt{\frac{M}{m}}

Let R=\sqrt{\frac{M}{m}}

Then, \frac{x}{D-x}=R

x=DR-xR

x+xR=DR

x(1+R)=DR

x=\frac{DR}{1+R}

b.We have to find the ratio R of the mass of the mass of the planet to the mass of the moon when x=\frac{2}{3}D

Net force is zero

F_m=F_M

\frac{Gm_0m}{(D-\frac{2}{3}D)^2}=\frac{Gm_0M}{\frac{4}{9}D^2}

\frac{m}{\frac{D^2}{9}}=\frac{9M}{4D^2}

\frac{M}{m}=4

Hence, the ratio R of the mass of the planet to the mass of the moon=4:1

8 0
4 years ago
A student sees a newspaper ad for an apartment that has 1330 square feet of floor space. How many square meters of area are ther
hichkok12 [17]
One square meter equals 10.7 feet. 

1330 ft^2 * \frac{1m}{10.7ft^2} = 123.561
8 0
4 years ago
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