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viva [34]
3 years ago
15

A 100kg cannon at rest contains a 10kgcannonball. when fired,

Physics
1 answer:
slega [8]3 years ago
4 0

Answer:

9 m/s

Explanation:

mass of cannon, M = 100 kg

mass of cannon ball, m = 10 kg

velocity of cannon ball, v = 90 m/s

Let the recoil velocity of cannon is V.

Us ethe conservation of linear momentum, as no external force is acting on the system, so the linear momentum of the system is conserved.

Momentum before the firing = momentum after the firing

M x 0 + m x 0 = M x V + m x v

0 = 100 x V + 10 x 90

V = - 9 m/s

Thus, the recoil velocity of cannon is 9 m/s.

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V125BC [204]
To find acceleration you subtract the final velocity and subtract it from the initial velocity and you divide the difference by the total time.

so you take the final velocity which is 0 m/s because the car comes to a complete stop.

then you subtract that from the initial which is 26 m/s

in other words:

0m/s - 26 m/s = -26 m/s

then you divide it by the total time which is 13 s

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The volume of a gas at 59.0kPa is 600ml. if the pressure is increase to 138.0kPa, what will be the new volume?
likoan [24]

Answer:

<h3>The answer is 256.52 mL</h3>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

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We have the final answer as

<h3>256.52 mL</h3>

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a=0 (m/s^2)
Thus when we apply the equation
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7 0
4 years ago
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