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Scilla [17]
3 years ago
12

The graph of function f has two vertical asymptotes and a horizontal asymptote at y = 2. Which function could be function f?​

Mathematics
1 answer:
tatyana61 [14]3 years ago
7 0

Answer:

It's f(x)=2x^2/x^2+2x-3.

Step-by-step explanation:

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Which equation in point-slope form contains the point (4, –1) and has slope 3?
Andrew [12]

Answer:

y+1=3(x-4)

Step-by-step explanation:

Hi there!

We are given a slope of 3 and a point (4,-1).

We need to find the equation of the line in point-slope form

Point-slope form is given as y-y1=m(x-x1), where m is the slope, and (x1,y1) is a point

We have all of the needed information to substitute into the formula

First, let's label the values of everything to avoid any confusion

m=3

x1=4

y1=-1

now substitute into the formula *remember, the formula has SUBTRACTION, and we have a NEGATIVE number, so we'll end up subtracting a negative*

y--1=3(x-4)

simplify

y+1=3(x-4)

That's it!

Hope this helps :)

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Is a vertical line that passes through (7,-3).
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Answer:

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I hope this is right

Step-by-step explanation:

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