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Elden [556K]
3 years ago
14

In the data set shown below, what is the value of the quartiles? {56, 58, 64, 68, 72, 75, 78} A. Q1 = 58; Q2 = 68; Q3 = 73.5 B.

Q1 = 61; Q2 = 68; Q3 = 73.5 C. Q1 = 75; Q2 = 68; Q3 = 58 D. Q1 = 58; Q2 = 68; Q3 = 75
Mathematics
2 answers:
Marysya12 [62]3 years ago
8 0

Answer:

(C) Q1: 55.5 Q2: 110 Q3: 295

Step-by-step explanation:

Given the dataset:

There are 25 items in the dataset.

To find Q2, We divide it into two equal parts and consider the middle term

Therefore: Q2 =110

Q1 = the median of the lower half of the data set.

Q3 = is the median of the upper half of the data set.

In the lower half of the data

Since there are even number of terms,

Median = (55+56)/2=55.5

Therefore: Q1=55.5

In the upper half of the data

Since there are even number of terms,

Median = (239+351)/2=295

Therefore: Q3=295

Q1: 55.5,  Q2: 110,  Q3: 295

The correct option is C.

Tresset [83]3 years ago
4 0

Answer:

6yx

Step-by-step explanation:

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=======================================================

Explanation:

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Allowing us to say,

\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\

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