Answer:
Step-by-step explanation:
let : x the length and y the width .... ( x > y and x ; y reals numbers )
the perimeter is : 2(x+y)
2(x+y) = 55...(1)
x/y = 7/4 ...(2)
by (2) : x = (7/4)y
subsct in (1) : 2( (7/4)y +y ) =55
(7/2)y +2y =55
multiply by 2
7y +4y = 110
11y = 110
y = 10
x = (7/4)(10)
x = 35/2
Gggggggggggggggggggggggggggggggggggggg. It would be 7
8x + 7y = 39
4x - 14y = -68
(multiply each term in second equation by -2)
8x + 7y = 39
-8x + 28y = 136
(add both equations)
35y = 175
(divide both sides by 35)
y = 5
(substitute value of y in one of the equations)
8x + 7(5) = 39
8x + 35 = 39
8x = 4
x = 1/2
(x, y) = (1/2, 5)
Five goes into 11, two times. So each friend gets two cookies and 1/5 of the last one. So the answer is 2 and
1/5
