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Put the phase of mitosis or mitosis in order from first to last

vladimir1956 [14]

The phases of mitosis in order from first to last are: Interphase, prophase, metaphase, anaphase, and telophase & cytokinesis.

7 0

3 years ago

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A dog runs 50 meters north 40 meters east and 20 meters south what is the displacement

Allisa [31]

So....
imagine the x and y axis or draw it on a piece of paper, a white board or even on your wall if you like. I'm kidding just draw it on a piece of paper

50m up and 20m down
the dog's displacement is 50 - 20 which is 30
your answer is 30m north

3 0

3 years ago

Vector A has magnitude of 8units and makes an angle of 45° with the positive x-axis. Vector B also has the same magnitude of 8un

iragen [17]

Answer:

Explanation:

Because vectors have direction and x and y components you can't just add them and say that their length is 16 because A is 8 units and so is B. What you're actually finding is the magnitude and direction of the vector that results from this addition. The magnitude is the length of the resultant vector, which comes from the x and y components of A and B, and the direction is the angle between the resultant vector and the positive x axis. To add the vectors, then, we need to find the x and y components of each. We'll do the x components of A and B first so we can add them to get the x component of C. Since x values are directly related to cos, the formula to find the x components of vectors is

$V_x=Vcos\theta$ which is the magnitude of the vector (its length) and the angle. Finding the x components of A:

$A_x=8.0cos45$ so

$A_x=5.7$ and for B:

$B_x=8.0cos180$ since the negative x axis is the 180 degree axis and

$B_x=-8.0$ If we add them, we get

$C_x=-2.3$

Now onto the y components. The formula for that is almost the same as the x components except use sin instead of cos:

$A_y=8.0sin45$ so

$A_y=5.7$ and

$B_y=8.0sin180$ so

$B_y=0$ If we add them, we get

$C_y=5.7$

Now for the final magnitude:

$C_{mag}=\sqrt{(-2.3)^2+(5.7)^2}$ and

$C_{mag}=6.1 units$ and now onto the direction.

The x component of C is positive and the y component is negative, which means that the direction has us at an angle is quadrant 2; we add 180 to whatever the angle is. Finding the angle:

$tan^{-1}(\frac{C_y}{C_x})=(\frac{5.7}{-2.3})$ = -68 + 180 = 112 degrees

The resultant vector of A + B has a magnitude of 6.1 and a direction of 112°

Do the same thing for subtraction, except if you're subtracting B from A, the direction that B is pointing has to go the opposite way. That means that A doesn't change anything at all, but B is now pointing towards 0.

$A_x=5.7$ (doesn't change from above)

$B_x=8.0cos0$ and

$B_x=8.0$ so

$C_x=13.7$ and

$A_y=5.7$ (also doesn't change from above)

$B_y=8.0sin0$ so

$B_y=0$ and

$C_y=5.7$ and for the magnitude:

$C_{mag}=\sqrt{(13.7)^2+(5.7)^2$ so

$C_{mag}=15units$ and for the direction:

$tan^{-1}(\frac{5.7}{13.7})=23$ and since both x and y components of C are in Q1, we add nothing.

And you're done!!!

3 0

3 years ago

It takes fifteen minutes to complete a drilling operation using a lathe. the duration of this operation is known as _____ time.

dalvyx [7]

I think the correct answer would be processing time. The time of fifteen minutes describes how long the whole operation was done or how long is the whole processing of drilling. Hope this answers the question. Have a nice day.

8 0

3 years ago

The peak of the trajectory occurs at time t1. This is the point where the ball reaches its maximum height ymax. At the peak the

Digiron [165]

Part B
What are the values of the intial velocity vector components v0,x and v0,y (both in m/s) as well as the acceleration vector components a0,x and a0,y (both in m/s2)? Here the subscript 0 means "at time t0."
15.0, 26.0, 0, -9.80

Part C
What are the values of the velocity vector components v1,x and v1,y (both in m/s) as well as the acceleration vector components a1,x and a1,y (both in m/s2)? Here the subscript 1 means that these are all at time t1.
15, 26, 0, -9.81

7 0

3 years ago